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ale4655 [162]
3 years ago
7

mc040-1.jpg Suppose TD=SG and MD=SL. What additional information is needed to prove the two triangles congruent by SAS?

Mathematics
1 answer:
nikklg [1K]3 years ago
6 0
AC is congruent to BD
- CBA is congruent to CDA
- AC is perpendicular to BD
- BAC is congruent to DAC

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ziro4ka [17]

Answer:

f(g(x)) = 3(2x^3 -2)^2 - 4x + 2, and f(g(3)) = 3[2(3)^3 -2]^2 -4*3 -2 = 8102

Step-by-step explanation:

because for f(g(x)), the g(x) is the input of f(x), so put 2x^3 -2 into 3x^2 -4x +2, and you will get f(g(x)). because g(3) is the input of f(x), so find g(3) first, the answer is 52, and then put it back into f(x) which will be f(52) =[3(52)^2 - 4(3) +2], then the answer should be 8102.

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3 years ago
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Step-by-step explanation:

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Z=a/b+c/d solve for A
PilotLPTM [1.2K]

Answer: a=\frac{b(zd-c)}{d}

Step-by-step explanation:

Having the following equation given in the exercise:

z=\frac{a}{b}+\frac{c}{d}

You can solve for "a" following this procedure:

1. You can apply the Subtraction property of equality and subtract \frac{c}{d} from both sides of the equation:

z-(\frac{c}{d})=\frac{a}{b}+\frac{c}{d}-(\frac{c}{d})\\\\z-\frac{c}{d}=\frac{a}{b}

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

\frac{zd-c}{d}=\frac{a}{b}

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:

(b)(\frac{zd-c}{d})=(\frac{a}{b})(b)\\\\a=\frac{b(zd-c)}{d}

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3 years ago
Help ill give brainlest pls
Mamont248 [21]

Answer:

The answer is C. The translation of a line is a pair of parallel lines.

Step-by-step explanation:

A, B, and D are true. C is <em>not</em> true, and therefore the correct answer.

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2 years ago
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Sergeu [11.5K]

Answer:

10

Step-by-step explanation:

substitute -8 into x.

f(-8)=-8+18=10

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2 years ago
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