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3 years ago

What is the estimation of 94,903?

Mathematics

2 answers:

timofeeve [1]3 years ago

7 0

95,000 is the answer cause 9 is greater

denis-greek [22]3 years ago

3 0

Well, it could be 95,000 or 94,900 depending on what you want.

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Shauna spent $175 on a pair of shoes.She spent 1/9 of the remaining money on a shirt.If he still had 4/7of his moneyleft,how muc

KIM [24]

Answer:

$490

Step-by-step explanation:

Shauna spent $175 on a pair of shoes.

She spent 1/9 of the remaining money on a shirt.

If he still had 4/7 of his money left,how much did he have at first ?

Solution:

Let at first, Shauna have = $x$

Money spent on a pair of shoes = $175

Remaining money = $x-175$

As she spent 1/9 of the remaining money on a shirt.

Money spent on shirt = $\frac{1}{9} \times(x-175)=\frac{x}{9} -\frac{175}{9}$

As he still had $\frac{4}{7}$ of his money left:-

Money left = $\frac{4}{7}\ of\ his\ money=\frac{4x}{7}$

Money left with Shauna = Total money, she had at first -(Money spent on a pair of shoes + Money spent on shirt )

$\frac{4x}{7} =x-(175+{\frac{x}{9} -\frac{175}{9} )\\\\\\$

$\frac{4x}{7} =x-(\frac{175}{1} -\frac{175}{9} +\frac{x}{9} )\\\\ \frac{4x}{7} =x-(\frac{1575-175}{9} +\frac{x}{9} )\\\\ \frac{4x}{7}=x-(\frac{1400}{9} +\frac{x}{9} )\\ \\ \frac{4x}{7}=x-\frac{1400}{9} -\frac{x}{9}$

Subtracting both sides by $x$ and adding both sides by $\frac{x}{9}$

$\frac{4x}{7} -x+\frac{x}{9} =-\frac{1400}{9} -x+\frac{x}{9} +x-\frac{x}{9}$

Taking LCM of 7 and 9, we get 63

$\frac{36x-63x+7x}{63} =-\frac{1400}{9} \\ \\ -\frac{20x}{63}=-\frac{1400}{9}$

Adding both side by -

$\frac{36x-63x+7x}{63} =-\frac{1400}{9} \\ \\ \frac{20x}{63}=\frac{1400}{9}$

By cross multiplication:

$20x\times9=1400\times63\\180x=88200\\$

Dividing both sides by 180

$x=490$

Therefore, total $490, she had at first.

3 0

3 years ago

Help!?Who can help me with this?

Sonbull [250]

What he/she said is correct

6 0

3 years ago

Find the integral of 3/sqrt of 1-4x^2

erastovalidia [21]

$\int {\frac{3}{\sqrt{1-4x^{2}}}} \, dx$
$= 3\int {\frac{1}{\sqrt{1-4x^{2}}}} \, dx$
$= 3\int {\frac{1}{\sqrt{4(\frac{1}{4} - x^{2})}}} \, dx$
$= \frac{3}{2}\int {\frac{1}{\sqrt{\frac{1}{4} - x^{2}}}}\, dx$

$= \frac{3}{2}sin^{-1}(2x) + C$

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3 years ago

David and Mark are marking exam papers. Each set takes David 24 minutes and Mark 1 hour. Express the times David and Mark take a

attashe74 [19]

Answer:

2:5

Step-by-step explanation:

david=24mins

mark = 1hour

change 1 hour to mins

DAVID=24

MARK=60

24:60

THEN SIMPLIFY

24/60

=2/5

2:5

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3 years ago

Eric drives 62 mph for 5.25 hours. How far does he drive?

11111nata11111 [884]

Answer:

325.5

Step-by-step explanation:

multiply 62 and 5.25 to get 325.5

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3 years ago

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