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Sloan [31]
3 years ago
6

Can someone help me with this one

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0
The answe is 4..you can see the pattern if you add 4 in the x
sergey [27]3 years ago
6 0
The answer is 4. If you add 4 to any of the x values, it equals the y value next to it
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9 3/4 - 1 1/4 in simplest form
Kipish [7]
8 1/2 would be the answer to this question
4 0
3 years ago
Which property of multiplication is used in the multiplication below?
olasank [31]
Zero property because you are using zeros to multiply
4 0
3 years ago
Suppose the equation of the axis of symmetry for a quadratic function is x = 3 and one of the x-intercepts is 8. What is the oth
soldi70 [24.7K]

Answer:

-2

Step-by-step explanation:

The axis of symmetry divides the quadratic exactly in half. If one x-intercept is 8, then the other will be the same distance on the other side of it. 8 is 5 from 3 where the axis of symmetry is. So 3-5 = -2. -2 will be the other intercept.

8 0
3 years ago
Find the value of x<br><br><br><br><br><br> x=?
soldi70 [24.7K]

Answer:

x = 135 degrees

Step-by-step explanation:

For any simple n-gon, the sum of the interior angles is 180(n − 2) degrees. (n is the number of vertices)

180(6-2)=180(4)=720

the shape already has 2 90-degree angles, subtract both of those from total interior angle sum

720-90-90=540

the 4 angles left must make up 540 degrees

540/4=135

x=135 degrees

4 0
2 years ago
Read 2 more answers
Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi
Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_{KMN} is equal to the area A_{MNL}. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

6 0
3 years ago
Read 2 more answers
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