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<h3>I'm solving it using substitution method:-</h3>
<h3>7x+2y=3 {given}</h3>
<h3>=>7x=3-2y</h3>
<h3>=>x=(3-2y)/7-------(1)</h3>
<h3>x-3y=30 {given}</h3>
<h3>=>x=30+3y</h3>
<h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3>
<h3>=>3-2y=210+21y</h3>
<h3>=>3-210=21y+2y</h3>
<h3>=>-207=23y</h3>
<h3>=>y= -207/23= -9</h3>
<h3>putting the value of y on eqn(1):-</h3>
<h3>x=(3-2y)/7</h3>
<h3>x=>(3-2(-9))/7=(3+18)/7=21/7=3</h3>
<h2>Hence, x=3, y= -9</h2>
✌️✌️❤️❤️
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Answer:(f*g)(x)= 21x^2 -29x -10
Step-by-step explanation:
(3x-5)(7x+2)
21x^2-35x+6x-10
21x^2-29x-10
Answer:
26 + y
----------
9y
Step-by-step explanation:
Your using parentheses here would remove a great deal of ambiguity. Looking at your 8-y/3y + y+2/9y - 2/6y, I have interpreted it to mean:
(8-y)/3y + (y+2)/9y - (2/6)y. For example, without parentheses, your 8-y/3y might be interpreted differently, as 8 - y/(3y), or 8 - 1/3.
Looking at (8-y)/3y + (y+2)/9y - (2/6)y again, we see three different denominators: 3y, 9y and 6 y. The LCD here is 9y. Multiplying all three terms of (8-y)/3y + (y+2)/9y - (2/6)y by the LCD, we get:
3(8-y) + (y+2) + 3y. We must now divide this by the LCD:
3(8-y) + (y+2) + 3y
--------------------------
9y
Next we need to perform the indicated multiplication:
24 - 3y + y + 2 + 3y
----------------------------
9y
and then to combine like terms:
24 + 2 - 3y + y + 3y, 26 + y
---------------------------- or -----------
9y 9y
Answer:3 terms and a degree of 9
Step-by-step explanation:
19.6 would be the area of a single base circle πr² is the area formula
