All categories

2 years ago

Simplify (x^2)^35x/6x^215x^3

Mathematics

1 answer:

nasty-shy [4]2 years ago

8 0

When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2

<h3>Data obtained from the question</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Simplification =?

<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]

Recall

(M^a)^b = M^ab

Thus,

(x^2)^3 = x^6

[(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]

Recall

M^a × M^b = M^(a+b)

Thus,

x^6 × 5x = 5x^(6 + 1) = 5x^7

6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5

[x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5

Recall

M^a ÷ M^b = M^(a - b)

Thus,

5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2

Therefore,

[(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2

Learn more about algebra:

brainly.com/question/2768008

#SPJ1

You might be interested in

If a machine that prints designs on T-shirts prints 500 shirts in 3 hours, how many hours will it take to print designs on 1,800

vivado [14]

Answer:

The answer is D. 12

Step-by-step explanation:

In 3 hours, it prints 500 shirts. That means 6 hours it will print 1,000 shirts, in 9 hours it will print 1,500 shirts, and in 12 hours, it will print 2,000 shirts. So in 12 hours, it will print 1,800 shirts.

4 0

3 years ago

The table shows the gallons filled in a pool over time (ASAP)

satela [25.4K]

Answer:

125, 250, 500, 625

Step-by-step explanation:

As you can see, half of the pool is 500. 2 halves would make a whole, concluding the pool is 1000. Then for the 1/8, do 1000/8. Getting 125. 1000/4 would make it 250. And then taking the 125 from the earlier division of 8 and multiplying by 5 will get you 625. Hope this helps <3

5 0

3 years ago

-3x+24y-36 factor the expression

Brilliant_brown [7]

-3x+24y-36 . You notice that the GCF =3 (that means the number that divides all factors)
3( - x + 8y -12) or you can put the "-" sign outside the parenthesis, but mind you , you will have to change all signs in the parenthesis:

-3( x - 8y +12)

5 0

3 years ago

lyudmila [28]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Side BC

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

$\therefore \tt \boxed{ \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} = { \bigg(\frac{BC}{EF} \bigg)}^{2} }$