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myrzilka [38]
3 years ago
10

Mrs Lim packs 35 big and small bags of candies for her pupils. Each big bag contains 12 candies and each small bag contains 7 ca

ndies. The bags contain 300 candies altogether. How many big bags of candies and how many small bags of candies does she pack?
Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

there are 11 big-bags and 24 small-bags.

Step-by-step explanation:

there are x big-bags and y small-bags.

so now we can know:

(1) x + y = 35

(2) 12x + 7y = 300

in (1),we can do like this:

both left and right x7

then (x + y)x7 = 35 x 7

then 7x + 7y = 35 x 7  

then 7x + 7y = 245

now,

(1)7x + 7y =245

(2)12x + 7y = 300

we can both left and right do this: (2) - (1)

then

(12x + 7y) - (7x + 7y) = 300 -245

then

12x + 7y - 7x - 7y = 300 -245

then

12x - 7x +7y - 7y =300 -245

then

5x =55

then

5x ÷ 5 = 55 ÷ 5

then

x = 11

because

x + y =35;x=11

so

11 + y =35

11+ y -11 = 35 -11

then

y = 24

now we know:there are 11 big-bags and 24 small-bags.

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For the functions f(x)=2x^2+3x+9 and g(x)=−3x+10 find (f⋅g)(x) and (f⋅g)(1)
pashok25 [27]

Step-by-step explanation:

f(x)=2x²+3x+9

g(x) = - 3x + 10

In order to find (f⋅g)(1) first find (f⋅g)(x)

To find (f⋅g)(x) substitute g(x) into f(x) , that's for every x in f (x) replace it by g (x)

We have

(f⋅g)(x) = 2( - 3x + 10)² + 3(- 3x + 10) + 9

Expand

(f⋅g)(x) = 2( 9x² - 60x + 100) - 9x + 30 + 9

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Group like terms

(f⋅g)(x) = 18x² - 120x - 9x + 200 + 30 + 9

(f⋅g)(x) = 18x² - 129x + 239

To find (f⋅g)(1) substitute 1 into (f⋅g)(x)

That's

(f⋅g)(1) = 18(1)² - 129(1) + 239

= 18 - 129 + 239

We have the final answer as

<h3>(f⋅g)(1) = 128</h3>

Hope this helps you

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