Im feeling good today and who ever sees this its your lucky day<br> here is 100 points

What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?

german

For this case we have the following function:
$f(x) = tan(\frac{x^2}{9})$
The average rate of change is given by:
$AVR = \frac{f(x2) - f(x1)}{x2- x1}$
Evaluating the function for the given interval we have:
For x = 1.25:
$f(1.25) = tan(\frac{1.25^2}{9})$
$f(1.25) = 0.18$
For x = 2:
$f(2) = tan(\frac{2^2}{9})$
$f(2) = 0.48$
Then, replacing values we have:
$AVR = \frac{0.48 - 0.18}{2 - 1.25}$
$AVR = 0.4$
Answer:
the average value of on the closed interval [1.25, 2] is:
$AVR = 0.4$

3 0

2 years ago

City planners are planning to build a new community park. They agree that the park will be rectangular in shape, but the propose

podryga [215]

Answer:

(c) 714.96 = 21.6(w +4.7)

Step-by-step explanation:

The area of the rectangular park will be the product of its length and width. This relation is used to write an equation to find the original width of the park.

<h3>Width</h3>

Let w represent the original width of the park in meters. The new width is 4.7 meters more, so is represented by (w +4.7).

<h3>Other dimensions</h3>

The length of the park is given as 21.6 meters. The area is given as 714.96 square meters.

<h3>Area formula</h3>

The various dimensions of the park are related by the area formula:

A = LW

714.96 = 21.6(w +4.7)

4 0

1 year ago

NEED NOW PLEASE..........

Harlamova29_29 [7]

Answer:

The answer is 6 feet below the surface of the water.

Step-by-step explanation:

So the fish started out as 12m below the surface then went 3m down. If you add 12m and 3m you'll 15m, then minus with a 9m to came up with 6m. But the fish is still below surface, which gives you the answer of " 6 feet below the surface"

<em><u>Hopes this helped you :)</u></em>

8 0

2 years ago

Need help thank you:)

inna [77]

Answer:

$F = 1.8C + 32$