The answer would be A.) Web pages provide information, while web applications allow the user to do something. a web page is for relaying information. (you can relate this to a book. a page in a book gives you information.) while an application allows you to perform an action.
Answer:
The nature of computers and code, what they can and cannot do.
How computer hardware works: chips, cpu, memory, disk.
Necessary jargon: bits, bytes, megabytes, gigabytes.
How software works: what is a program, what is "running"
How digital images work.
Computer code: loops and logic.
Big ideas: abstraction, logic, bugs.
The reason that you have not been locked out after several failed PIN login attempts is that your laptop does not have a TPM chip, and you have not set up BitLocker for lockout.
Technology known as Trusted Platform Module (TPM) is made to offer hardware-based, security-related functionality. Designed to perform cryptographic operations, a TPM chip is a safe crypto-processor. Malicious software cannot interfere with the TPM's security capabilities, and the chip has numerous physical security features to prevent tampering. Utilizing TPM technology has a number of major benefits, including the following:
- Cryptographic keys should be created, stored, and used sparingly.
- Utilize the burnt-in RSA key of the TPM to authenticate platform devices using TPM technology.
- By recording security metrics, you can assist in ensuring platform integrity.
To learn more about TPM click here:
brainly.com/question/10742732
#SPJ4
Hey there! Hello!
I believe that you can click a button that has something to do with decreasing the font size, to go along with the question, perhaps the decrease font size button. Sometimes these buttons are represented with minus signs or arrows pointing downwards, among other symbols that convey that the font size will be decreasing.
I hope this helped you out! Feel free to ask me any additional questions if you have any. :-)
Answer:
Answer explained below
Explanation:
void bubbleSort(int X[], int Y[], int n)
{
int i, j;
for (i = 0; i < n-1; i++)
// Last i elements are already in place
for (j = 0; j < n-i-1; j++)
if (X[j] > X[j+1])
{
swap(X[j],X[j+1])
swap(Y[j],Y[j+1]);
}
if (X[j] == X[j+1]&&Y[j]<Y[j+1])
{
swap(X[j],X[j+1])
swap(Y[j],Y[j+1]);
}
}
Since the above algorithm contains 2 nested loops over n.
So, it is O(n^2)
