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3 years ago

6

Beau buys a 3-pound bag of trail mix for a hike. He wants to make one-ounce bags for his friends with whom he is hiking. How man

y one-ounce bags can he make?

1 answer:

den301095 [7]3 years ago

4 0

1 pound = 16 ounces

3 pounds = 3*16 ounces
3 pounds= 48 ounces

So, he can make 48 one-ounce bags

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Two points on the line are (0, 4) and (7, 18). Use the points to first determine the slope and y-intercept. Then write the equat

Nadya [2.5K]

9514 1404 393

Answer:

a. m = 2; y intercept = (0, 4); y = 2 x + 4

Step-by-step explanation:

The slope can be found using the formula ...

m = (y2 -y1)/(x2 -x1)

m = (18 -4)/(7 -0) = 14/7

m = 2

The y-intercept is the first given point: (0, 4).

The equation for the line in slope-intercept form is

y = mx + b

Here, we have m=2 and b=4, so the equation is ...

y = 2x +4

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3 years ago

3. The product of 7/10 and another factor

kicyunya [14]

The correct answer is d 7/7

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4 years ago

Use the drop-down menus to choose steps in order to correctly solve 3+4d−14=15−5d−4d for d.

Kisachek [45]

Answer:

d=2

Step-by-step explanation:

SHOWN BELOW

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3 years ago

Read 2 more answers

Based on the table, what is Nick's rate?

Nookie1986 [14]

7 yrds/sec because in the course of two seconds, he runs 14 yrds divide that by 2 to get 7 yrds/sec. you can allo chech with the next time which is 3 seconds more and he goes 21 yards more.

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3 years ago

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago