39in³ is a required volume.
Solution given:
for upper one
length[l]=8in
breadth[b] =3in
height[h]=1in
now
volume [V1]=l×b×h=8×3×1=24in³
again for lower one:
length[l]=6-1=5in
breadth[b] =3in
height[h]=1in
volume [V2]=l×b×h=5×3×1=15in³
Again
total volume =V1+V2=24in³+15in³=39in³
[m(100cm/m)(in/2.54cm)(ft/12)]^2=(25/7.62)^2 ft^2
(9*16)m^2(25ft^2/7.62m^2)(sheets/(4*8)ft^2)≈48.44 sheets
In reality you must buy complete sheets, or integer values, so you would need 49 sheets to cover the floor :P
Answer:
4 is c and 5 s a
Step-by-step explanation:
is this helps pls say thanks
