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ZanzabumX [31]
3 years ago
9

C=5/9(f-32) given the temperature in August on a summer day is 33

Mathematics
1 answer:
S_A_V [24]3 years ago
5 0
Is the 33 in celsius or fahrenheit
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Convert the repeating decimal to a rational number 0.4000
atroni [7]

Answer:

<u>IF the repeating decimal is 0.4000</u> the rational number is 0.4

5 0
4 years ago
Read 2 more answers
What is the area of this trapezoid (the right leg says 8 btw)
alekssr [168]

The answers have square roots among the choices so we probably shouldn't use that calculator button.

We can't just apply the area of the trapezoid formula

A = \frac 1 2(b + t) h

where b is the bottom base, t the parallel top, and h the height, because we don't know the top t.

It will be 10 less the leg of that right triangle, which we calculate as

l = \sqrt{8^2 - (4\sqrt{3})^2} = \sqrt{64 - 48} = \sqrt{16}=4

Now we can apply the trapezoid formula. We have

b = 10, \qquad t=10-4=6, \qquad h= 4\sqrt{3}

A = \frac 1 2(b + t) h = \frac 1 2 (10 +6)(4 \sqrt{3}) = 32 \sqrt{3}

Choice b

7 0
3 years ago
Please Help Me!!!!!!!!!!!​
jonny [76]

Answer:

f ≥ -2

Step-by-step explanation:

6f ≥ -12

Divide both sides by 6;

f ≥ - 2

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B2%7D%2B1%5Cright%29%5Cleft%285%2B%5Csqrt%7B2%7D%5Cright%29" id="TexFormula
dsp73
<h3>Solution:</h3>

( \sqrt{2}  + 1)(5 +  \sqrt{2}) \\  =  \sqrt{2}  (5 +  \sqrt{2} ) + 1(5 +  \sqrt{2} ) \\  = 5 \sqrt{2}  + 2 + 5 +  \sqrt{2}  \\  = 7 + 6 \sqrt{2}

<h3>Answer:</h3>

7 + 6√2

5 0
3 years ago
Read 2 more answers
Solve the system by finding the reduced row-echelon form of the augmented matrix.
Alex

Answer:

The reduced row-echelon form is

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The solutions to the system of equations are:

y=-2z-3,\:x=-6z-10

Step-by-step explanation:

To solve this system of linear equations,

x-4y-2z=2\\2x-11y-10z=13\\-x+6y+6z=-8

you must:

Step 1: Transform the augmented matrix to the reduced row echelon form.

In an augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

This is the augmented matrix that represents the system.

\left[ \begin{array}{cccc} 1 & -4 & -2 & 2 \\\\ 2 & -11 & -10 & 13 \\\\ -1 & 6 & 6 & -8 \end{array} \right]

It can be transformed by a sequence of elementary row operations to the matrix.

There are three kinds of elementary matrix operations.

  1. Interchange two rows (or columns).
  2. Multiply each element in a row (or column) by a non-zero number.
  3. Multiply a row (or column) by a non-zero number and add the result to another row (or column).

Using elementary matrix operations, we get that

Row Operation 1: add -2 times the 1st row to the 2nd row

Row Operation 2: add 1 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1/3

Row Operation 4: add -2 times the 2nd row to the 3rd row

Row Operation 5: add 4 times the 2nd row to the 1st row

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

Step 2: Interpret the reduced row echelon form

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

x+6z=-10\\y+2z=-3\\0=0

The system has infinitely many solutions.

y=-2z-3,\:x=-6z-10

4 0
4 years ago
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