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lara [203]
3 years ago
12

Find the unknown side length, x. Write your answer in simplest radical form.

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0
The side x is the hypotenuse of the triangle.

And we know that the leg that is labeled with a line is also 6.

Use the Pythagorean theorem and solve for x.

a² + b² = x²
3² + 6² = x²
9 + 36 = x²
45 = x²
√45 = x
√9×5 = x
√9√5 = x
3√5 = x

The answer is 3√5

Hope this helps :)

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The square root of a product of two positive real numbers is the product of their square roots. Write an algebraic expression ba
Sliva [168]

Step-by-step explanation:

  • The square root of a product of two positive real numbers is the product of their square roots.

Let 4 and 5 be the two positive real number. The square root of a product of 4 and 5 is the product of their square roots.

\sqrt{4\cdot 5}

=\sqrt{20}

=\sqrt{2^2\cdot \:5}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

=\sqrt{5}\sqrt{2^2}

so

=\sqrt{5}\sqrt{2^2}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a

\sqrt{2^2}=2

Therefore,

\sqrt{4\cdot \:5}=2\sqrt{5}

NOW SOLVING BY APPLYING RADICAL RULE such that

\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

\sqrt{4\cdot 5}=\sqrt{4}\sqrt{5}

as

\sqrt{2^2}=2

so

     =2\sqrt{5}            

Hence, The square root of a product of two positive real numbers is the product of their square roots.

5 0
3 years ago
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BigorU [14]

Answer:

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hammer [34]

Answer: 53.79

Step-by-step explanation:

3 0
3 years ago
HELP
PIT_PIT [208]

Try your best but I think the answer is the first one.

50 + 4 = 54

MARGIN OF ERROR - 4%

54 + 4 = 58

THE FIRST SHOULD BE YOUR ANSWER.

7 0
3 years ago
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nordsb [41]
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3 years ago
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