F(n+1)=f(n)-5. If f(1)=100, what is f(6)
1 answer:
Answer:
<em>75</em>
Step-by-step explanation:
Given:
f(1) = 100
f(n+1) = f(n) - 5
Solve for:
f(6)
Solution:
f(1) = 100
f(2) = f(1) - 5 = 100 - 5 = 100 - 1 x 5 = f(1) - 1 x 5
f(3) = f(2) - 5 = 100 - 5 - 5 = 100 - 2 x 5 = f(1) - 2 x 5
...
f(n) = f(n - 1) - 5 = 100 - (n-1) x 5 = f(1) - (n-1) x 5
=> f(6) = f(1) - (6-1) x 5 = 100 - 5 x 5 = 100 - 25 = 75
Hope this helps!
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