F(x)= 2/(x+1) and g(x)= -x2-12 => f(-7)= ? , g(2.5)= ?, g(f(- 0.5))= ?
In the expression of the function f(x) we will replace instead of x the number in bracket (-7) => f(-7) = 2/(-7+1)= 2/-6 = - 1/3
In the expression of the function g(x) we will replace instead of x number in bracket (2.5) => g(2.5) = - (2.5)squared -12= - 6.25 -12= - 18.25
Expression f(g(x)) or g(f(x)) is multiplication (composition) of the reflecting of functions f and g. We will do this in the following way => g(f(x))= g(2/(x+1))= -(2/(x+1))2 - 12= -(4/(x+1)2) -12= -4-12(x+1)2/(x+1)2=> we will replace instead of x the number in bracket (-0.5) or (-1/2) => g(f(-1/2) = -4-12((-1/2)+1)2/ ((-1/2+ 1)2= -4-12(1/2)2/(1/2)2=-4-12*(1/4)/(1/4)= (-4-3)/(1/4)=-28
Eaisier way => f(-1/2)=2/((-1/2)+1)=2/(1/2)= 4 g(4) -(4)2-12 = -16-12= -28
Zero. because every worker will be afraid of to be retiered
Answer:
3/6
Step-by-step explanation:
Answer:
The exponential function that passes through (2,36) is:
.
Step-by-step explanation:
We are asked to find which function passes through the point (2,36).
i.e. we will put the input value '2' in the following given functions and check which gives the output value as '36'.
1)
now we put x=2.
hence option 1 is correct.
2)
Now we put x=2.
Hence, option 2 is incorrect.
3)
Now we put x=2
Hence, option 3 is incorrect.
4)
Now we put x=2.
Hence, option 4 is incorrect.
Hence, option 1) is correct.
i.e. The exponential function that passes through (2,36) is:
Use dot product
a=(x1,y1) and b=(x2,y2)
a.b=/a/*/b/ cos x
a.b mean dot product of two vectors
a.b is equals x1*y1+x2*y2
