I had to look for the figure and here is my answer:
Given the circle attached to this question, the area of the sector AOB is the 60 of the fractional part of the area of the circle O. Since the whole circle is 360, this would be 60/360. To simplify this, we would arrive to the final answer of 1/6. Hope this helps.
x^8/x^5=27
x=3 when you flip the equation (rounded number)
Answer:
2 1/2 in.
Step-by-step explanation:
6 - 3 1/2 this is the answers
Angle-5 and angle-7 are 'vertical angles', so they're equal,
and we can write ...
<u>10x- 9 = 9x</u>
Subtract 9x from each side: x - 9 = 0
Add 9 to each side: <u> x = 9</u>
Now that we know what 'x' is, we can find the size of Angles-5 and -7 .
Angle-7 = 9x = 81° .
Now look at Angle-6 ... the one that's the answer to the problem.
Angle-6 and -7 together make a straight line, so they must
add up to 180°.
<u>Angle-6 + 81° = 180°</u>
Subtract 81° from each side: Angle-6 = <em>99° .</em>
