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3 years ago

What are the solutions to the equation? use the quadratic formula to solve the equation. 2y²-10y+8=0

Mathematics

1 answer:

Ludmilka [50]3 years ago

4 0

The answer is D for this one

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B. Distinct Parallel lines.

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wlad13 [49]

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Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teac

agasfer [191]

Answer:

a) $\frac{8}{9}$ =0.89

b) 0.8413

Step-by-step explanation:

we know that

$P(║ x -\mu║ \leq k\sigma) \geq 1 -\frac{1}{k^2}$

$so, \mu = 150, \sigma = 20$

$k = \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3$

$P(║ x -150 ║ \leq 3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}$

x - N(150, 20^2)

$P(X \leq 170) = 0.8413447$

check

$P norm = \frac{170 - 150}{20}= 0.8413447$

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