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creativ13 [48]
3 years ago
11

A manufacturer of new light bulbs claims the average lifetime of its long-life bulb is more than 4000 hours. To test this claim,

a reputable testing firm took a random sample of 100 bulbs and life tested them. The testing firm found the average life of the sample to be 4500 hours with a sample standard deviation, s = 400 hours. The value of the test statistic for this problem isA 1.25B -1.25C 12.5D -12.5E None of the values listed
Mathematics
1 answer:
natka813 [3]3 years ago
5 0

Answer: C. 12.5

Step-by-step explanation:

Given : A manufacturer of new light bulbs claims the average lifetime of its long-life bulb is more than 4000 hours.

Population mean :  \mu=4000

Sample size : n= 100

Sample mean : \overline[x}=4500

Standard deviation: s=400

The value of test-statistic is given by :-

z=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}\\\\\Rightarrow\ z=\dfrac{4500-4000}{\dfrac{400}{\sqrt{100}}}\\\\\Rightarrow\ z= 12.5

Hence, the value of the test statistic for this problem is 12.5.

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Step by step solution :

Step  1  :

           x

Simplify   —

           4

Equation at the end of step  1  :

       x

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       4

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2.1   Subtracting a fraction from a whole  

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          13     13 • 4

    13 =  ——  =  ——————

          1        4    

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Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions  

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

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Step  3  :

When a fraction equals zero :

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Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Here's how:

 52-x

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                     -x = -52  

Multiply both sides of the equation by (-1) :  x = 52  

7 0
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