Answer:
65/72
Step-by-step explanation:
cot is simply cosine over sine or the tangant flipped
the cos (c)=65/97
sin (c) = 72/97
cot would be (65/97)/(72/97)
How do you divide fractions? By multiplying the reciprocal!
cot would be 65/97 * 97/72
the 97s cross out.
65/72
Answer:
KL ≈ 1.94
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos48° =
=
=
( multiply both sides by KL )
KL × cos48° = 1.3 ( divide both sides by cos48° )
KL =
≈ 1.94 ( to the nearest hundredth )
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2
12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15) V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656
Answer:
The Sum of the areas of theses triangles is 169/3.
Step-by-step explanation:
Consider the provided information.
The hypotenuse of an isosceles right triangle is 13 inches.
Therefore,

Then the area of isosceles right triangle will be: 
Therefore the area is: 
It is given that sum of the area of these triangles if this process is continued infinitely.
We can find the sum of the area using infinite geometric series formula.

Substitute
in above formula.



Hence, the Sum of the areas of theses triangles is 169/3.
So firstly, multiply both sides by 5/7 (reciprocal of 7/5): 
Next, add both sides by 45 and your answer will be: 