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Shtirlitz [24]
3 years ago
10

The quantities x and y are proportional.

Mathematics
2 answers:
irga5000 [103]3 years ago
8 0

Answer:

r=1/4

Step-by-step explanation:

y=1/4*x

2=1/4*8

1/4*8=2

musickatia [10]3 years ago
8 0
Y=1/4 8/2 is correcto
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Find the missing terms in the following geometric sequence.
Dmitrij [34]

Answer: D. 36, 108

Step-by-step explanation:

In the geometric series the ratio of two consecutive term is constant and this ratio is called the common ratio,

Let n be the common ratio of the given series,

Then the GP will be,

12, 12×n, 12×n×n, 324,

Again by the definition of Geometric series,

\frac{12n}{12} = \frac{324}{12n^2} \implies n^3 = 27\implies n = 3

Thus, the required series is,

12, 12×3, 36×3, 324

= 12, 36, 108, 324

⇒ Option D is correct.

5 0
3 years ago
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Gary works as a sales representative in a clothing store. He gets a fixed salary of $1,500 per month. He also gets a commission
Lelechka [254]

x represents the total sales and y represents the total amount of money that Gary earns.

Gary's monthly salary = 1500

His commission = 10% of his sales

= \frac{10}{100} x

= 0.1x

So, total amount of money Gary earns is y = 0.1x + 1500.

3 0
4 years ago
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What is the approximate volume of the cylinder use 3.14 to approximate show work
topjm [15]
<span>2463.01 is the answer. So A is the correct answer</span>
5 0
4 years ago
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Let f(x)=4x+1 and g(x)3x+k find value of k if fog(x)=gof(x)​
kogti [31]

Answer:

\huge\boxed{k=\dfrac{2}{3}}

Step-by-step explanation:

f(x)=4x+1\\\\g(x)=3x+k\\\\(f\circ g)(x)=f\bigg(g(x)\bigg)=4(3x+k)+1=(4)(3x)+(4)(k)+1=12x+4k+1\\\\(g\circ f)(x)=g\bigg(f(x)\bigg)=3(4x+1)+k=(3)(4x)+(3)(1)+k=12x+3+k\\\\(f\circ g)(x)=(g\circ f)(x)\iff12x+4k+1=12x+3+k\qquad|\text{cancel}\ 12x\\\\4k+1=3+k\qquad|\text{subtract 1 from both sides}\\\\4k=2+k\qquad|\text{subtract}\ k\ \text{from both sides}\\\\3k=2\qquad|\text{divide both sides by 3}\\\\k=\dfrac{2}{3}

5 0
3 years ago
A parabola is defined by the equation x2 = 3/4 y. In which direction will the parabola open?
TEA [102]
The equation of parabola is x^2=\dfrac{3}{4}y. 
The canonical equation of parabola is y^2=2p x and this parabola has branches that go in positive direction of x-axis.

Since in your equation x is changed to y and y to x, then the <span>branches of the parabola go in positive y-axis direction, the vertex is placed at the origin. 
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8 0
4 years ago
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