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Shtirlitz [24]
3 years ago
10

The quantities x and y are proportional.

Mathematics
2 answers:
irga5000 [103]3 years ago
8 0

Answer:

r=1/4

Step-by-step explanation:

y=1/4*x

2=1/4*8

1/4*8=2

musickatia [10]3 years ago
8 0
Y=1/4 8/2 is correcto
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What is the cot in simplest fraction form????<br> Please help been stuck for 30 minutes!!
Fantom [35]

Answer:

65/72

Step-by-step explanation:

cot is simply cosine over sine or the tangant flipped

the cos (c)=65/97

sin (c) = 72/97

cot would be (65/97)/(72/97)

How do you divide fractions? By multiplying the reciprocal!

cot would be  65/97 * 97/72

the 97s cross out.

65/72

5 0
3 years ago
Simple geometry please help<br><br> Find KL. Round to the nearest hundredth.
vivado [14]

Answer:

KL ≈ 1.94

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos48° = \frac{adjacent}{hypotenuse} = \frac{JL}{KL} = \frac{1.3}{KL} ( multiply both sides by KL )

KL × cos48° = 1.3 ( divide both sides by cos48° )

KL = \frac{1.3}{cos48} ≈ 1.94 ( to the nearest hundredth )

6 0
3 years ago
Can someone please help me with 10-16 it’s due tomorrow!!! Please
VMariaS [17]
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2

12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15)  V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656
7 0
3 years ago
The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian
Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }

Then the area of isosceles right triangle will be: A=\frac{1}{2} x^2

Therefore the area is: A=\frac{169}{4}

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

S=\frac{a}{1-r}

Substitute a=\frac{169}{4} \ and\ r=\frac{1}{4} in above formula.

S=\frac{\frac{169}{4}}{1-\frac{1}{4}}

S=\frac{\frac{169}{4}}{\frac{3}{4}}

S=\frac{169}{3}

Hence, the Sum of the areas of theses triangles is 169/3.

7 0
2 years ago
G=7/5(p-45)<br> The solution is p=__g+___<br> Simplify your answers. Type an integer or fraction.
amm1812

So firstly, multiply both sides by 5/7 (reciprocal of 7/5): \frac{5}{7}g=p-45

Next, add both sides by 45 and your answer will be: \frac{5}{7}g+45=p

7 0
3 years ago
Read 2 more answers
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