Answer:
Area of circle A =113.14 mm²
Area of circle b = 314.29 mm²
Area of circle C = 452.57 mm²
Area of circle A = 254.57 mm²
2.25 times
Step-by-step explanation:
Area of a circle = nr²
where n = 22/7
r = radius
Circle A's radius = 6mm
Circle B's radius = 6mm + 4mm = 10mm
Circle C's radius = 10mm + 2mm = 12mm
Circle D's radius = 12mm - 3mm = 9mm
Area of circle A = (22/7) x 6² = 113.14 mm²
Area of circle b = (22/7) x 10² = 314.29 mm²
Area of circle C = (22/7) x 12² = 452.57 mm²
Area of circle A = (22/7) x 9² = 254.57 mm²
Number of times the area of circle D is greater than that circle A = Area of circle D / Area of circle A
254.57 mm² / 113.14 mm² = 2.25 times
Answer: 61.33333.... wpm
Step-by-step explanation:
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- The equation :
Area = length x width
- Substitute the values in :
Area = (x - 5)(x - 5 + 22)
(Note : the 'x' is for the algebraic expression x in the example above)
- Now you have to simplify the second parenthesis:
Area = (x - 5)(x + 17)
- Now expand :
Area = x^2 + 17x - 5x - 85
- Simplify by collecting like terms :
Area = x^2 + 12x - 85
(Note : x^2 means x squared)
Now you have your answer as:
x^2 + 12x - 85 feet^2
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F(x) = -4sin(2x + π) - 5
<u>Amplitude</u>
A = -π
<u>Period</u>
<u>2π</u> = <u>2π</u> = π
B 2
<u>Phase Shift</u>
<u>-C</u> = <u>-π</u> = ≈ 1.57<u>
</u> B 2<u>
</u>