To find the surface area, you need to do the following:
A side of the figure is a trapezoid, so you should do 13+5x7 (since there are 2 of the same sides there is no need to divide by two.) and it should equal 126. To find the area of the top of the figure, you need to do 5x2 which equals 10. The area of the bottom of the figure is 26 (13x2), then do 2x3x2 to get the sides on the left and right of the figure. After all of this, add them together. (126+10+26+12=174.)
The surface area should be 174mm.
Answer:
58°
Step-by-step explanation:
<MQR = <XQL (vertically opposite angles)
28 + 5b = 70 - 2b
28 - 70 = -2b - 5b
-42 = -7b
-42/-7 = b
6 = b
<MQR = 28 + 5b
= 28 + 5(6)
= 28 + 30
= 58°
Answer:
-5
Step-by-step explanation:
-7 - (-2)
-7 + 2
Example: If you owe someone $7, and you give them $2, how much do you still owe? You are owing him $7 so it's a negative and you give him $2 which is a negative as well since you are giving it to him. So, to answer how much do you still owe, you would add $2 to the $7 you owed, so now, you owe him $5, which is a negative since you OWE him.
Hope this helps:)
Answer:
Step-by-step explanation:
When does the value of f(x) = (1/2)x equal the value of g(x) =2x+8?
Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)
