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4 years ago

15

Solve 3^2x+3 = 243 for x. A. x = 1 B. x = 10 C. x = 2 D. x = 2/5

1 answer:

Gnoma [55]4 years ago

8 0

First get rid of the exponent: 6x + 3 = 243. then subtract 3 from both sides: 6x = 240. lastly divide both side by 6: x = 40. be sure to check your work by plugging it back in.

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The office supplies store where you work has a 15 % off sale. If the customer purchases $250 in office supplies how much will th

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250 • .15 = 37.50
$37.50$

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3 years ago

I need help writing the first 5 terms of the sequence!

Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

$a_{1}=1$

$a_{n}=a_{n-1}+3$

General term of the arithmetic sequence.

$a_{n}=a_{n-1}+d$ , where d is the common difference.

d = 3

$a_{n}=a_{n-1}+3$

Put n = 2 in $a_{n}=a_{n-1}+3$ , we get

$a_{2}=a_1+3$

$a_{2}=1+3$

$a_2=4$

Put n = 3 in $a_{n}=a_{n-1}+3$ , we get

$a_{3}=a_2+3$

$a_{3}=4+3$

$a_3=7$

Put n = 4 in $a_{n}=a_{n-1}+3$ , we get

$a_{4}=a_3+3$

$a_{4}=7+3$

$a_4=10$

Put n = 5 in $a_{n}=a_{n-1}+3$ , we get

$a_{5}=a_4+3$

$a_{5}=10+3$

$a_5=13$

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0

3 years ago

lilavasa [31]

Those two functions just miss each other so there are no real solutions. Every polynomial with complex coefficients has complex solutions.

$2x^2 + 2 = 3x$

$2x^2 - 3x = -2$

$2( x^2 - \frac 3 2 x) = -2$

$x^2 - \frac 3 2 x = -1$

$x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2$

$(x - \frac 3 4)^2 = -\frac 7{16}$

$x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}$

$x = \frac 3 4 \pm \frac i 4 \sqrt{7}$

$x = \frac 1 4(3 \pm i \sqrt{7})$

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3 years ago

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That's it? How many cupcakes

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3 years ago

Read 2 more answers

Dominic ordered 210 pens. He divided them equally among his 10 friends. One of his friends, Benjamin, already had 27 pens. Then,

photoshop1234 [79]

Answer:

35

Step-by-step explanation:

210/10=21 pens per friend

21+27=48 pens for benjamin

48-13=35 pens left

benjamin has 35 pens now

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3 years ago