Does this polygon have point symmetry?

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

6 0

No is doesn't it has a rotational symmetry but not point symmetry

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Please help!

loris [4]

m∠B = 33° is the answer.

<u>Step-by-step explanation:</u>

If two triangles ΔABC and ΔMOP are similar, then their corresponding angles are congruent.

In any triangle, sum of the measure of the angles add up to 180°.

∠A+ ∠B+ ∠C = 180°

∠A ≅ ∠M

∠B ≅ ∠O

∠C ≅ ∠P

So we can add as,

∠A + ∠B+ ∠P = 180°

45° + ∠B + 102° = 180°

∠B + 147° = 180°

∠B = 180° - 147° = 33°

8 0

4 years ago

Given two vectors A=2i+3j+4k,B=i-2j+3k find the magnitude and direction of sum<br>(physics question)

Law Incorporation [45]

Answer:

$Magnitude =\sqrt{59} \\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}}$

Step-by-step explanation:

A=2i+3j+4k

B=i-2j+3k

Sum of the vectors:

A + B = 2i+3j+4k + i-2j+3k = 3i + j + 7k

$Magnitude =\sqrt{3^2 + 1^2+ 7^2} \\\\Magnitude =\sqrt{9+1+49} \\\\Magnitude =\sqrt{59}$

Direction of the sum of the vectors:

$\widehat{A + B} =\frac{\overrightarrow{A + B}}{Magnitude\: of \:\overrightarrow{A + B}} \\\\\widehat{A + B} =\frac{3i + j + 7k}{\sqrt {59}} \\\\\widehat{A + B} =\frac{3}{\sqrt {59}} i +\frac{1}{\sqrt {59}} j+\frac{7}{\sqrt {59}} k\\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}} \\\\$