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Oksana_A [137]
3 years ago
14

AMELIA IS SHARING 4 SLICES OF CHEESE WITH 5 FRIENDS. HOW MUCH CHEESE WILL EACH PERSON GET? EXPLAIN HOW YOU DECIDED.

Mathematics
1 answer:
Degger [83]3 years ago
3 0

Answer:

well this is very easy all you have to do is divide 4 by 5 and you will get 4 with a remander of 1 or 0.8 or if this was a real life scenario then you could just take that extra slice and cut it in five ways. hope this helped! can i get brainiest plzz? im only ONE away from getting up to expert!

Step-by-step explanation:

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Besties pls help did I get these right?
lana66690 [7]

Answer:

Yep!

Step-by-step explanation:

I'm not 100% sure if your first one is correct, but I know the second one is! Great job :)

8 0
3 years ago
Round to the nearest hundred thousand 992,449
Lesechka [4]
The hundred thousand column is the 6th column so you look at the 5th number and round
9 rounds up to 0
but this also changes the 900000 to 1000000
so 992449 = 1000000 to nearest hundred thousand
8 0
3 years ago
Read 2 more answers
3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k
Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt

Evaluate the integral to solve for y :

\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt

\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x

\displaystyle y = x^3+2x^2+kx - 2

Use the other known value, f(2) = 18, to solve for k :

18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}

Then the curve C has equation

\boxed{y = x^3 + 2x^2 + 2x - 2}

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2

The slope of the given tangent line y=x-2 is 1. Solve for a :

3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1

So, the point of contact between the tangent line and C is (-1, -3).

7 0
2 years ago
下100<br> +1<br> Can yhu show work
Hitman42 [59]

Answer:

101

Step-by-step explanation:

   

             101

           +     1

       ________

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3 0
3 years ago
Is the following conditional true?
kakasveta [241]

Answer:

Yes

Step-by-step explanation:

3 0
3 years ago
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