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Svetradugi [14.3K]
3 years ago
6

If f(x) = x2 and g(x) = x - 3, then g(f(x)) = ?

Mathematics
1 answer:
pogonyaev3 years ago
3 0
The answer is A- x^2-3 because f(x) is plugged into the “x” of g(x)
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○B. \frac{\sqrt{6}}{2}

Step-by-step explanation:

Trigonometric Identities

\frac{y}{r} = sin\:θ

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\frac{y}{x} = tan\:θ

\frac{r}{x} = sec\:θ

\frac{r}{y} = csc\:θ

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<u>Radius Formula</u>

{y}^{2} + {x}^{2} = {r}^{2}

{[-\sqrt{15}]}^{2} + {[-\sqrt{10}]}^{2} = {r}^{2} → 15 + 10 = {r}^{2} → 25 = {r}^{2}\\ \\ 5 = r

* Since we are talking about radii, we only want the NON-NEGATIVE root.

In this case, we will not be using the radius in our ratio, according to the trigonometric identity above because we are using the <em>tangent</em><em> </em>ratio:

\frac{\sqrt{6}}{2} = \frac{-\sqrt{15}}{-\sqrt{10}} = \sqrt{1\frac{1}{2}}

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Step-by-step explanation:

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