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posledela
2 years ago
7

Colton read 21 1/4 pages in 1 1/4 hours. If he continues reading at the

Mathematics
1 answer:
True [87]2 years ago
4 0

Answer:

1,020

Step-by-step explanation:

First step.

Since he can read 21 1/4 pages in 1 and 1/4 hour then we got to know how many pages he can read in one hour right? so we need to divide.

Second step.

So we will need to divide 21 1/4 divided by 1 and 1/4 which will give us 17 which is the pages he will read in one minute.

Third step.

After you get that then we multiply it by the hour which is 60 minutes in an hour so,

60 x 17 = 1,020

Which gives us the answer

Hope that helps =)

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2 years ago
(Crys) Im in 11 grade and in applied geometry I need help crys and how do you show
Snowcat [4.5K]

Answer:

1. -2/3        3. -5/4         5. 3/2          FOR THE REST OF THE PARTS LOOK THROUGH THE EXPLANATIONS

Step-by-step explanation:

Before I start the workings, I'll give a little explanation on this topic.

So, the equation of a straight line is

y = mx + c

where x and y are any coordinates of any point on the line.

m is the gradient or slope

m can be calculated using 2 formulas,

formula 1: Rise/Run

where rise is the how much a graph goes upwards or downwards, if its upwards use positive integer and if its downwards use negative integer.

Run is how much a graph moves to the right or to the left, if it moves to the right is is positive, if it moves to the left it is negative.

Formula 2: (y2-y1)/(x2-x1)

the values of these are taken through any 2 coordinates on the line.

and c is the y-intercept(the point where the line crosses the y-axis.

<u>MOVING TO ANSWERING NOW</u>

1. Dotted points on the line are (1,0) and (4,-2)

Formula of slope,

U can use any of the 2 formulas given above

I'll show both for this question

m = (y2-y1)/(x2-x1) = (-2-0)/(4-1) = -2/3

OR

m = rise/run = where rise is -2 and run is 3 so -2/3

2. TRY DOING THIS ONE YOURSELF

For the next part I'll do 3 and 5 for your understanding, try doing 2 and 4 on your own to understand.

3. Coordinates given (13,1) and (1,16)

m = (y2-y1)/(x2-x1) = (16-1)/(1-13) = 15/-12  simplify this and it becomes -5/4

5.  (-8,-14) and (-10,-17)

m =  (y2-y1)/(x2-x1) = (-17-(-14))/(-10-(-8)) = -3/-2 = 3/2

FOR THE NEXT PART I'LL DO 7,8 AND 10 FOR YOU, TRY DOING 9 ON YOUR OWN FOR PRACTICE.

I WILL ALSO ATTACH FILES FOR THE NEXT PARTS IN ORDER OF QUESTIONS SO SEE THEM.

7. y = x + 3 this means y = 1x +3 which means:

1 is the gradient

3 is the y-intercept

so 1 as a fraction is 1/1 which means rise is one upwards and run is 1 to the right.

Now go to the graph on the y-axis and plot the point 3, (0,3) is your y-intercept. From their rise by one and run by one this will lead u to point (1,4)

Mark both these points and make a line through them.

8. x = -5

now look at this equation in the form of y = mx + c

0 = 1x + 5 the means y is 0 and it is already told in the question that x = -5

if u rearrange 0 = 1x + 5 it will give you x = -5

now when y is  0 x = -5 put a point on the coordinate (-5,0) and draw a vertical straight line.

10. y = (1/4)x - 1

slope is 1/4 which means rise is 1 and run is 4

y-intercept is -1

now go to y=-1 which is the coordinate (0,-1) and rise by one and run by 4, this will take u to the coordinate (4,0) now put a dot on both coordinates, connect them and put a line through them.

3 0
1 year ago
In a zoo there are zebras and peacocks sharing the same area. There is a total of 14 zebras and peacocks. If you count, there is
Arturiano [62]
If we take the number of Zebras to be x and that of peacocks to be y
Then x + y = 14
A zebra has 4 legs while a peacock has 2 legs, 
Therefore the total number of legs will be 4x + 2y  which is equal to 36 .
Therefore, we have two equations 
    x + y = 14
   4x + 2y = 36    solving them simultaneously using elimination
   
4x +2y = 36
2x + 2y = 28 ( multiplying the first equation by 2 to eliminate y)
     2x = 8 ( subtracting the equations)
        x = 4  
       y = 14 -(4) 
          = 10
Therefore, there are 4 zebras and 10 peacocks in the zoo
3 0
3 years ago
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