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Alex17521 [72]
3 years ago
9

What is the constant proportionality in the equation y = 6x?

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

Answer: the constant of proportionality is x

Step-by-step explanation:

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The numbers 0,1/2, -53 and 0.433 all belong to which category ?
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0, 1/2, -53, and 0.433 all belong in rational category
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A confidence level of 95% mean
USPshnik [31]

Answer:

A 95% confidence interval is a range of values that you can be 95% certain contains the true mean of the population. ... The 95% confidence interval defines a range of values that you can be 95% certain contains the population mean.

Step-by-step explanation:

hope that helps

8 0
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Solve the equation cot 2x + cot x =3
rusak2 [61]

tan2x*cotx - 3 = 0

We know that: tan2x = sin2x/cos2x and cotx = cosx/sinx

==> sin2x/cos2x *cosx/sinx = 3

Now we know that sin2x = 2sinx*cosx

==> 2sinxcosx/cos2x * cosx/sinx = 3

Reduce sinx:

==> 2cos^2 x/ cos2x = 3

Now we know that cos2x = 2cos^2 x-1

==> 2cos^2 x/(2cos^2 x -1) = 3

==> 2cos^2 x = 3(2cos^2 x -1)

==> 2cos^2 x = 6cos^2 x - 3

==> -4cos^2 x= -3

==> 4cos^2 x = 3

==> cos^2 x = 3/4

==> cosx = +-sqrt3/ 2

<span>==> x = pi/6, 5pi/6, 7pi/6, and 11pi/6</span>

3 0
3 years ago
What is the answer?<br><br> (Please help)
k0ka [10]

\dfrac{bc}{b}=\dfrac{b}{b}\cdot\dfrac{1}{c}=1\cdot\dfrac{1}{c}=\boxed{\dfrac{1}{c}}\\\\\dfrac{\not b^1}{\not b_1c}=\dfrac{1}{1c}=\boxed{\dfrac{1}{c}}

8 0
3 years ago
11 POINTS PLZ HELP EMERGENCY
Bad White [126]

Part A

The given expression is:

(-5(1+2i)+3i(3-4i)

We expand to get:

-5-10i+9i-12i^2

Note that i^2=-1

12-5-10i+9i

-5-10i+9i+12

7-i

Part Bi)

The given expression is;

\sqrt{-50}

We simplify to get:

\sqrt{25\times 2\times -1}

\sqrt{25\times} \sqr{2}\times \sqrt{-1}

Note that:

\sqrt{-1}=i

5\sqr{2}i

This is now of the form a+bi, where a=0,b=5\sqr{2}.

This explains why it is a complex number;

Part bii)

The given expression is :

\frac{\sqrt{-50} }{\sqrt{5}}

We simplify to get

\sqrt{\frac{-50 }{5}}

\sqrt{-25}

\sqrt{-25}=\sqrt{25}\times \sqrt{-1}

\sqrt{-25}=5\times i

\sqrt{-25}=5i

Part C

We want to simplify:

i^{22}

We rewrite in terms of i^2

i^{22}=(i^2)^{11}

i^{22}=(-1)^{11}

i^{22}=-11

5 0
3 years ago
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