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zepelin [54]
3 years ago
8

Plz answer me

Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

1.

Suppose quarter of jon's flowers are 5. So total number of flowers will be 4×5 =20.

2. Dionne has 23 sweets.

Step-by-step explanation:

2.

Let dionne has "x" sweets

And jack has

Jack sweets = 3x

Jack has 46 more sweets than than dionne so

Jack = x + 46

Now,

3x = x + 46

2x = 46

x = 46/2

x = 23.

So dionne has 23 sweets and jack jas 69.

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Elsa tries to solve the following equation, and determines there is no solution. Is she correct? Explain.
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Elsa's answer is incorrect since there is a solution of the given equation. In the given logarithmic problem, we need to simplify the problem by transposing log2(3x+5) in the opposite side. The equation will now be log2x-log2(3x+5)=4. Using properties of logarithm, we further simplify the problem into a new form log (2x/6x+10)=4.  Then transform the equation into base form 10^4=(2x/6x+10) and proceed in solving for x value which is equal to 1.667. 
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Read 2 more answers
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

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Answer:

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Step-by-step explanation:

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