Question

the sum of two polynomials 10a2b2 – 8a2b + 6ab2 – 4ab + 2. If one addend is –5a2b2 + 12a2b – 5, what is the other addend?

Answer 1

Combine the like terms to help oullmpvqf fvr

Answer 2

Answer:

$15a^2b^2-20a^2b+6ab^2-4ab+7$

Step-by-step explanation:

Given,

Sum of two polynomial = $10a^2b^2 - 8a^2b + 6ab^2 - 4ab + 2$

One addend = $-5a^2b^2 + 12a^2b - 5$

Let x be the other addend,

$\implies x + (-5a^2b^2 + 12a^2b - 5)=10a^2b^2 - 8a^2b + 6ab^2 - 4ab + 2$

$\implies x = 10a^2b^2 - 8a^2b + 6ab^2 - 4ab + 2-(-5a^2b^2 + 12a^2b - 5)$

$\implies x = 10a^2b^2 - 8a^2b + 6ab^2 - 4ab + 2+5a^2b^2 - 12a^2b + 5$

Combine like terms,

$x=15a^2b^2-20a^2b+6ab^2-4ab+7$

Hence, other addend is $15a^2b^2-20a^2b+6ab^2-4ab+7$