In 10 months 62.6 gallons were used find the unit rate

Luis wants to buy a home priced at $315,000. He plans to finance this amount less the down payment required. His mortgage paymen

OLEGan [10]

The correct option is that A. Luis is eligible for a home loan; he meets all of the requirements.

<h3>How to depict the information?</h3>

From the information, the monthly income will be:

= $91500/12

= $7625

The loan payment as a percentage will be:

= 2100/7625

= 27.54%

Since this is less than 28%, then Luis is eligible for a home loan; he meets all of the requirements.

Learn more about loan on:

brainly.com/question/26011426

#SPJ1

3 0

2 years ago

The sum of three consecutive even numbers is 114. what is the smallest of the three numbers?

saul85 [17]

Answer:

36

Step-by-step explanation:

Let's let n be any number.

If we multiply n by 2, we get 2n. Since anything multiplied by 2 is even, 2n <em>must</em> be even. Therefore, let 2n be our first number.

So, the consecutive even number will be (2n+2) followed by (2n+4).

We know that their sum must be 114. Therefore, we can write the following equation:

$(2n)+(2n+2)+(2n+4)=114$

Solve for n. Combine like terms on the left:

$6n+6=114$

Subtract 6 from both sides:

$6n=108$

Finally, divide both sides by 6. Therefore, the value of n is:

$n=108/6=18$

Therefore, our first even number is 2n or 2(18) which equates to 36.

And the consecutive even numbers will be 38 and 40.

So, the smallest of them, the first term, is 36.

4 0

3 years ago

Read 2 more answers

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

5+3=4d please help me

ad-work [718]

So the object of this problem is to find out the value of d.

To do this, first think about 5 + 3. This equals 8, right? So the value of d times 4 has to equal 8.

No other number besides 2 would make sense. 2 would equal d because 4 x 2 is 8, and 5 + 3 is 8.

So you would write the answer as:

5+3=4(2)

4 0

3 years ago

Read 2 more answers

I need help please help me im struggling please show WORK and tell me how to do it NO links please.

stellarik [79]

Answer:

- 7y +3 =-25

-7y=-25—3

-7y=-28

-7y÷-7= -28÷-7

y=4

Step-by-step explanation:

Take +3 to the side so that your variable and a constant is on their own sides. When a number goes over the equals sign the sign changes at becomes the inverse that's why l said - 3. You now calculate - 25—3 equals 28 then divide by 7 to find y and your y is 4.

3 0

3 years ago