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WARRIOR [948]
3 years ago
11

Find the point, M, that divides segment AB into a ratio of 3:2 if A is at (0, 15) and B is at (20, 0). A) (9, 6) B) (12, 6) C) (

12, 9) D) (9, 12)
Mathematics
2 answers:
Vsevolod [243]3 years ago
6 0

Step-by-step explanation:

0.16

kiruha [24]3 years ago
5 0

Answer:

Can you please give us a graph to know what it looks like

Step-by-step explanation:

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Francine and Cheryl received equal scores on a test made up of multiple choice questions and an essay. Francine got 34 multiple
kipiarov [429]

34x + 14 = 30x + 22
X is the amount the multiple choice question is worth. Both girls had the same test score so both are equal. Isolate X and that will be the value.

34x -( 30x) + 14 = 22
4x = 22 - (14)
4x = 8
4x \div 4 = 8 \div 4
x = 2

Plug 2 back in for x in the original equation to check and both girls recieved a 82%
5 0
3 years ago
How do I do this and whats the answer please
stepladder [879]

Answer:

slope= - 3/4

A(-4,3) and B(4,-3)

slope=m=\frac{y_B-y_A}{x_B-x_A} =\frac{-3-3}{4-(-4)} =\frac{-6}{8} =-\frac{3}{4}

3 0
4 years ago
1) Translate AQRS if Q(4,1), R(1.-2), S(2,3)<br> by the rule (x,y)=(x-3, y-4)
Gnesinka [82]

Answer:

Q=(1, -3)

R=(-2, -6)

S=(-1, -1)

7 0
3 years ago
Can I get help answering this question? It's a derivatives question, further info in the attachment.
Nadusha1986 [10]
\bf f(x)=|3+9x|\implies f(x)=\sqrt{(3+9x)^2}\implies f(x)=[(3+9x)^2]^{\frac{1}{2}}&#10;\\\\\\&#10;\cfrac{dy}{dx}=\stackrel{chain~rule}{\cfrac{1}{2}[(3+9x)^2]^{-\frac{1}{2}}\cdot 2(3+9x)\cdot 9}\implies \cfrac{dy}{dx}=\cfrac{9(3+9x)}{[(3+9x)^2]^{\frac{1}{2}}}&#10;\\\\\\&#10;\cfrac{dy}{dx}=\cfrac{27+81x}{|3+9x|}\\\\&#10;-------------------------------

\bf \textit{left-hand derivative at }x=-\frac{3}{9}\implies \cfrac{27+81x}{-(3+9x)}&#10;\\\\\\&#10;\cfrac{27+81\left( -\frac{3}{9} \right)}{-3-9\left( -\frac{3}{9} \right)}\implies \cfrac{27-27}{-3+3}\implies \stackrel{unde fined}{\cfrac{0}{0}}\\\\&#10;-------------------------------\\\\&#10;\textit{right-hand derivative at }x=-\frac{3}{9}\implies \cfrac{27+81x}{+(3+9x)}&#10;\\\\\\&#10;\cfrac{27+81\left( -\frac{3}{9} \right)}{3+9\left( -\frac{3}{9} \right)}\implies \cfrac{27-27}{3-3}\implies \stackrel{unde fined}{\cfrac{0}{0}}
8 0
3 years ago
When evaluating (3.25 times 10 Superscript 5 Baseline) (1.82 times 10 Superscript 3 Baseline), what will be the exponent of 10 i
boyakko [2]

Answer:

The exponent of 10 in the product is 8.

Step-by-step explanation:

The expression is as follows:

(3.25\times 10^{5})\cdot (1.82\times 10^{3})

Exponent rule:

a^{m}\times a^{n}=a^{m+n}

Simplify the expression as follows:

(3.25\times 10^{5})\cdot (1.82\times 10^{3})=3.25\times 10^{5}\times 1.82\times 10^{3}

                                        =(3.25\times 1.82)\times (10^{5}\times 10^{3})\\\\=5.915\times 10^{5+3}\\\\=5.915\times 10^{8}

Thus, the exponent of 10 in the product is 8.

3 0
3 years ago
Read 2 more answers
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