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2 years ago

Which equation is in point-slope form and depicts the equation of this line?

Mathematics

1 answer:

Elodia [21]2 years ago

7 0

We know
in the graph two points
point 1 (2,1) and point 2 (-1,-4)
the equation in point-slope form is ----------------> (y-y1)=m(x-x1)

step 1
find the value of m
m=(y2-y1)/(x2-x1)----------> (-4-1)/(-1-2)--------> m=5/3

step 2
with the point (-1,-4) and m=5/3
find the equation in point-slope form
(y-(-4))=(5/3)*(x-(-1))-------------> (y+4)=(5/3)(x+1)

the answer is the option d) ( y+ 4 ) =+ 5/3 ( x + 1 )

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Answer:

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Step-by-step explanation:

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2 years ago

What is the surface area of this design?<br> A.150in2<br> B.197in2<br> C.210in2<br> D.127in2

ANEK [815]

Answer:

197 in ^2 (answer B of the list)

Step-by-step explanation:

Notice that this figure has a total of 6 faces, four of which are rectangles (whose area is calculated as "base times height") and two trapezoids (whose area is (B+b)H/2 ).

The total surface area is therefore the addition of these six areas:

Rectangles:

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2 years ago

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oksian1 [2.3K]

Answer:

One Solution

Step-by-step explanation:

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2 years ago

A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st

shutvik [7]

Answer:

Equation of movement y(t)

$y(t)=sin(10t-\pi/2)$

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

$A=1\,inch$

The period depends on the mass and the spring constant.

The formula for the period is:

$T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s$

The model y(t) for the movement of the mass-spring system is

$y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)$

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2 years ago