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yKpoI14uk [10]
3 years ago
12

Which equation is in point-slope form and depicts the equation of this line?

Mathematics
1 answer:
Elodia [21]3 years ago
7 0
We know
in the graph two points
point 1 (2,1)  and point 2 (-1,-4)
the equation in point-slope form is ----------------> (y-y1)=m(x-x1)

step 1
find the value of m
m=(y2-y1)/(x2-x1)----------> (-4-1)/(-1-2)--------> m=5/3

step 2
with the point (-1,-4)  and m=5/3
find the equation in point-slope form
(y-(-4))=(5/3)*(x-(-1))-------------> (y+4)=(5/3)(x+1)

the answer is the option d) ( y+ 4 ) =+ 5/3 ( x + 1 )

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Consider 8x2 - 48x = -104.
ki77a [65]

Answer:

3+ 2\mathbf{i}

3- 2\mathbf{i}

Step-by-step explanation:

<u>Quadratic Equation Solving</u>

We have the equation:

8x^2-48x=-104

Divide by 8:

x^2-6x=-13

Now complete the squares so the left side is a perfect square of a binomial:

x^2-6x+9=-13+9=-4

Factoring the perfect square:

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Taking the square root:

x-3=\sqrt{-4}

The square root of a negative number is an imaginary number:

x-3=\pm 2\mathbf{i}

Solving for x:

x=3\pm 2\mathbf{i}

The solutions are:

3+ 2\mathbf{i}

3- 2\mathbf{i}

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