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Anna [14]
2 years ago
15

Here's a question from Ch-7 , Ex-14.3

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
6 0

<em>Graph</em><em> </em><em>is</em><em> </em><em>attached</em><em>!</em><em>~</em>

\rule{300pt}{3pt}

<em>The</em><em> </em><em>solution</em><em> </em><em>on</em><em> </em><em>paper</em><em> </em><em>is</em><em> </em><em>also</em><em> </em><em>attached</em><em> </em><em>with</em><em> </em><em>it</em><em>.</em><em>.</em>

OLga [1]2 years ago
4 0

The equation that represents the work done as a function of the distance is W= 5d

Represent the work done with w, and the distance travelled with d.

So, the proportional equation is:

W= Fd

Where:

F represents the proportional constant (Force)

Given that, the force is 5;

The equation becomes

W= 5d

Hence, the equation that represents the work done as a function of the distance is W= 5d

See attachment for the graph of the function

Read more about variation at:

brainly.com/question/6499629

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Consider a uniform distribution created by a random number generator. The distribution looks like a square with a length of 1 an
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The rigorous way to do this would be to compute a few integrals, but less work is usually better. Each of these probabilities correspond to the areas of rectangles. Each rectangle will have a height of 1, and the probability of interest will tell you everything you need to know about their lengths.

\mathbb P(0\le X\le0.4)\implies \text{length}=0.4\implies\mathbb P(0\le X\le0.4)=0.4\times1=0.4

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\mathbb P(X>0.6)=\mathbb P(0.60.6)=0.4

\mathbb P(X\le0.6)\implies \text{length}=0.6\implies\mathbb P(X\le0.6)=0.6

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3 0
3 years ago
Pren recorded this data set, which contains an outlier. 204, 216, 111, 224, 230, 211, 210, 198, 200, 218 What numbers represent
melamori03 [73]

Answer:

The correct option is D.

Step-by-step explanation:

The given data is

204, 216, 111, 224, 230, 211, 210, 198, 200, 218

Arrange the data in ascending order,

111, 198, 200, 204, 210, 211, 216, 218, 224, 230

The range is the difference between maximum value and minimum value.

Range=\text{upper limit}-\text{lower limit}

Range=230-111=119

Divide the data it two equal parts.

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Now divide the each in two equal parts.

(111, 198), 200, (204, 210), (211, 216), 218, (224, 230)

The mid value of first part is 200 and the mid value of second part is 218.

\text{lower quartile}=Q_1=200

\text{Upper quartile}=Q_3=218

Therefore option D is correct.

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Number of cans of paint:

c=\frac{579.6}{50} =11.59=12

Hope this helps

7 0
2 years ago
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