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Anna [14]
2 years ago
15

Here's a question from Ch-7 , Ex-14.3

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
6 0

<em>Graph</em><em> </em><em>is</em><em> </em><em>attached</em><em>!</em><em>~</em>

\rule{300pt}{3pt}

<em>The</em><em> </em><em>solution</em><em> </em><em>on</em><em> </em><em>paper</em><em> </em><em>is</em><em> </em><em>also</em><em> </em><em>attached</em><em> </em><em>with</em><em> </em><em>it</em><em>.</em><em>.</em>

OLga [1]2 years ago
4 0

The equation that represents the work done as a function of the distance is W= 5d

Represent the work done with w, and the distance travelled with d.

So, the proportional equation is:

W= Fd

Where:

F represents the proportional constant (Force)

Given that, the force is 5;

The equation becomes

W= 5d

Hence, the equation that represents the work done as a function of the distance is W= 5d

See attachment for the graph of the function

Read more about variation at:

brainly.com/question/6499629

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taki has her back to a wall. she starts to walk straight forward. she stops and turns 133° to the right and walks back in this d
Nikitich [7]
I'd like to assume that the triangle is a right triangle and you solve for x so...

133 + c = 180   (supplementary property to find one angle of triangle)
          c = 47

x = 180 - 90 - 47 (int. angles of triangle = 180)
   = 90 - 47
   = 43

Therefore, x is 43 degrees
6 0
3 years ago
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


7 0
3 years ago
How do i find the ratio 2:9
Ganezh [65]
The ratio of 2:9 has to be 2:9 do to the fact you can't simplify the fraction 2/9.
Hoped I helped.
6 0
3 years ago
Solve inverse operation of A - 5/6 = - 3 2/3
gayaneshka [121]

Answer:

- 2 5/6 = A

Step-by-step explanation:

- 3 2/3 + 5/6 = A

- 2 5/6 = A

3 0
3 years ago
Solve for x. Write the smaller solution first, and the larger solution second.<br>x^2 - 4x + 3 = 0​
love history [14]

Answer:

X=1 and X=3

Step-by-step explanation:

Factor: (x-3)(x-1)=0

Solve for X: X=1 and X=3

4 0
3 years ago
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