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Anna [14]
2 years ago
15

Here's a question from Ch-7 , Ex-14.3

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
6 0

<em>Graph</em><em> </em><em>is</em><em> </em><em>attached</em><em>!</em><em>~</em>

\rule{300pt}{3pt}

<em>The</em><em> </em><em>solution</em><em> </em><em>on</em><em> </em><em>paper</em><em> </em><em>is</em><em> </em><em>also</em><em> </em><em>attached</em><em> </em><em>with</em><em> </em><em>it</em><em>.</em><em>.</em>

OLga [1]2 years ago
4 0

The equation that represents the work done as a function of the distance is W= 5d

Represent the work done with w, and the distance travelled with d.

So, the proportional equation is:

W= Fd

Where:

F represents the proportional constant (Force)

Given that, the force is 5;

The equation becomes

W= 5d

Hence, the equation that represents the work done as a function of the distance is W= 5d

See attachment for the graph of the function

Read more about variation at:

brainly.com/question/6499629

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First right answer will get brainlist
creativ13 [48]
m- \frac{3}{4}=7 \frac{1}{8}   \\  \\ m= \frac{57}{8}+ \frac{3}{4}= \frac{57+6}{8}=    \frac{63}{8}= 7 \frac{7}{8}
7 0
3 years ago
Find an equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)
sattari [20]

Answer:

(x+5)^{2}=-4(y+3)

Step-by-step explanation:

Given:

Focus point = (-5, -4)

Vertex point = (-5, -3)

We need to find the equation for the parabola.

Solution:

Since the x-coordinates of the vertex and focus are the same,

so this is a regular vertical parabola, where the x part is squared. Since the vertex is above the focus, this is a right-side down parabola and p is negative.

The vertex of this parabola is at (h, k) and the focus is at (h, k + p). So, directrix is y = k - p.

Substitute y = -4 and k = -3.

-4 = -3+p

p=-4+3

p=-1

So the standard form of the parabola is written as.

(x-h)^{2}=4p(y-k)

Substitute vertex (h, k) = (-5, -3) and p = -1 in the above standard form of the parabola.

So the standard form of the parabola is written as.

(x-(-5))^{2}=4(-1)(y-(-3))

(x+5)^{2}=-4(y+3)

Therefore, equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)

(x+5)^{2}=-4(y+3)

7 0
3 years ago
St=18 and s = -4 where could T be located ?
Veseljchak [2.6K]

Answer:

14 or -22

Step-by-step explanation:

st=18

s=-4

-4+18=14

so t can be  at 14

or -4-18=-22

t can be at -22

3 0
2 years ago
Select all of the values for a that would make the inequality 2x &gt; 10 true.
babunello [35]

Answer:

Step-by-step explanation:

2x > 10       Divide by 2

2x/2 >10/2

x > 5

x cannot be 5 or anything smaller.

In English, x >5 reads as x must be greater than 5. (It can't be equal to 5 because 5 is not greater than 5)

The only two items that work are

8 which is greater than 5 and

30 which is also greater than 5

6 0
2 years ago
Find the value of the variable if P is between J &amp; K.<br><br> JP = 3y+1 ; PK = 12y - 4 ; JK = 75
LuckyWell [14K]
<span>JP + PK = JK
3y + 1 + 12y - 4 = 75
15y -3 = 75
15y = 75 +3
15y = 78
y = 78/15
y = 5.2

answer is </span><span>a. 5.2</span>
3 0
2 years ago
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