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Anna [14]
2 years ago
15

Here's a question from Ch-7 , Ex-14.3

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
6 0

<em>Graph</em><em> </em><em>is</em><em> </em><em>attached</em><em>!</em><em>~</em>

\rule{300pt}{3pt}

<em>The</em><em> </em><em>solution</em><em> </em><em>on</em><em> </em><em>paper</em><em> </em><em>is</em><em> </em><em>also</em><em> </em><em>attached</em><em> </em><em>with</em><em> </em><em>it</em><em>.</em><em>.</em>

OLga [1]2 years ago
4 0

The equation that represents the work done as a function of the distance is W= 5d

Represent the work done with w, and the distance travelled with d.

So, the proportional equation is:

W= Fd

Where:

F represents the proportional constant (Force)

Given that, the force is 5;

The equation becomes

W= 5d

Hence, the equation that represents the work done as a function of the distance is W= 5d

See attachment for the graph of the function

Read more about variation at:

brainly.com/question/6499629

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List the sides of △ABC in order from longest to shortest if the angles of △ABC have the following measures: m∠W = 4x - 1, m∠X =
Leto [7]

Answer:

w=4x

Step-by-step explanation:

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3 years ago
HELP!
wariber [46]

Answer: 50w+150>650

w>10

Step-by-step explanation: Subtract 150 on both sides, leaving 50w>500. Divide both sides by 50 to get w>10

3 0
3 years ago
Evaluate -(3-1)(3-2).
lina2011 [118]

Answer:

-2

Step-by-step explanation:

(−(3−1))(3−2)

=−2(3−2)

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5 0
3 years ago
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Amiraneli [1.4K]

A rectangle that maximize the enclosed area has a length 800 yards and width is 800 yards. The maximum area is 640,000 square yards.

In the given question we have to find the maximum area of the rectangular area.

Liana has 3200 yards of fencing to enclose a rectangle.

So we know that the perimeter of rectangle is

P= 2(l+b)

Let length of the rectangle is x yards and width is y yards.

So the equation should be

2(x+y) = 3200

Divide by 2 on both side we get

x+y = 1600................(1)

As we know the area of rectangle is

A = xy

From the equation the value of y is 1600-x.

Now putting the value of y

A = x(1600-x)

A = 1600x-x^2

On differentiating

dA/dx = 1600-2x

Putting dA/dx=0

1600-2x=0

Subtract 1600 on both side we get

-2x= -1600

Divide by -2 on both side we get

x = 800 yards

Now putting the value of x in the y=1600-x

y=1600-800

y=800 yards

So the maximum area is

A= 800*800

A= 640,000 square yards

Hence, a rectangle that maximize the enclosed area has a length 800 yards and width is 800 yards. The maximum area is 640,000 square yards.

To learn more about perimeter and area of rectangle link is here

brainly.com/question/16572231

#SPJ1

4 0
1 year ago
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