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2 years ago

Here's a question from Ch-7 , Ex-14.3

Mathematics

2 answers:

Lera25 [3.4K]2 years ago

6 0

Graph is attached!~

$\rule{300pt}{3pt}$

The solution on paper is also attached with it..

OLga [1]2 years ago

4 0

The equation that represents the work done as a function of the distance is $W= 5d$

Represent the work done with w, and the distance travelled with d.

So, the proportional equation is:

$W= Fd$

Where:

F represents the proportional constant (Force)

Given that, the force is 5;

The equation becomes

$W= 5d$

Hence, the equation that represents the work done as a function of the distance is $W= 5d$

See attachment for the graph of the function

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Find the 37th term of 352,345,338

Mariulka [41]

Answer:

$a_{37}=100$

Step-by-step explanation:

Given that,

A sequence 352,345,338.

First term = 352

Common difference = 345-352 = -7

We need to find the 37th term of the sequence.

The nth term of an AP is given by :

$a_n=a+(n-1)d\\\\a_{37}=352+36\times (-7)\\\\a_{37}=100$

So, the 37th term of the sequence is 100.

8 0

3 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0

2 years ago

An arithmetic sequence is given below.

Mashcka [7]

Given that $a_1=24$ and $a_2=17$ , if $a_n$ is an arithmetic sequence, then the common difference between successive terms is $d=a_2-a_1=17-24=-7$ .

You then have

$a_2=a_1+d$
$\implies a_3=a_2+d=a_1+2d$
$\implies a_4=a_3+d=a_1+3d$
$\implies \cdots\implies a_n=a_{n-1}+d=\cdots=a_1+(n-1)d$

So the explicit formula for the $n$ th term is

$a_n=24-7(n-1)$