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3 years ago

Please help! ;)------

Mathematics

1 answer:

AlexFokin [52]3 years ago

3 0

Answer:

The answer is c

Step-by-step explanation:

When there is a division with the sae variable and different exponent, you substract the exponent from the denominator from the one in the numerator.

$f^{9}/f^{3}=f^{9-3}$

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1.309 > 1.315 lololoolollooolllllllllllllllllllll

kvv77 [185]

Answer:

I’m confused on what you want me to do but that is false

Step-by-step explanation:

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2 years ago

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(11n - 3n) - n<br><br> Help plz desperate

Arlecino [84]

Answer: 7n

Step-by-step explanation:

Because....

First Remove the parentheses (a) = a

= 11n - 3n - n

Then add similar elements: 11n - 3n - n = 7n

= 7n

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3 years ago

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What is the solution to the given inequality?

SashulF [63]

1/2 - 1/4x ≥ -1/4

Combine 1/4x to get x/4:

1/2 - x/4 ≥ -1/4

Subtract 1/2 from both sides:

-x/4 ≥ -1/4 - 1/2

Simplify:

-x/4 ≥ -3/4

Multiply both sides by 4:

-x ≥ -3/4 * 4

-x ≥ -3

Multiply each side by -1 ( and since you are multiplying by -1, you also need to reverse the inequality sign)

Answer: x ≤ 3

5 0

2 years ago

A supervisor finds the mean number of miles that the employees in a department live from work. He finds x=29 and s=3.6 . Which s

qwelly [4]

Answer:

Option 3 is right

z37 is between 2 and 3 standard deviations of the mean.

Step-by-step explanation:

Let X be a random variable which represents the mean number of miles that the employees in a department live from work

X is normal (N(29,3.6)

WE have to find Z score for X

Z = $\frac{x-29}{3.6}$

=2.22

i.e. 37 is 2.22 std deviations from the mean.

In other words, z37 is between 2 and 3 standard deviations of the mean.

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2 years ago

Identifiy the initial amount a and the decay factor b in the exponential function y=5×0.5^×

xenn [34]

Answer:

$a=5\\ \\b=0.5$

Step-by-step explanation:

Given the exponential decay function $y=5\cdot (0.5)^x$

When $x=0,$ then

$y=5\cdot (0.5)^0=5\cdot 1=5,$

so the initial amount is $a=5$

The exponential decay function $y=a\cdot b^x$ has the decay factor $b.$

In your case, the eexponential decay factor is $b=0.5$

6 0

3 years ago