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uranmaximum [27]
4 years ago
12

Identify the constant of proportionality in the following tables: Need help ASAP

Mathematics
2 answers:
Angelina_Jolie [31]4 years ago
5 0

Answer:

<u>Constant of Proportionality = 2</u>

aleksley [76]4 years ago
4 0

The second one is 2

The third one is 6

And the fourth one is 2.5

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Help me asap
sasho [114]

Answer:

6p =120

Step-by-step explanation:

well the p's are very close together in a sense that we are going to multiply instead of add because they the p's would have space in between

6 * 20 = 120

so p= 20

6 0
3 years ago
Read 2 more answers
Why does (x-2)^2+9=0 have no real solutions?
alex41 [277]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± \sqrt{-9}

\sqrt{-9} yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to \sqrt{-9} are said to be imaginary, that is ± 3i

where i = \sqrt{-1}

If interested investigate further.

7 0
3 years ago
The figures below are similar.
jeyben [28]

Answer:

S=98

Step-by-step explanation:

If S2 is 196 we can divide that by two and get our answer: s=98

7 0
4 years ago
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
4 years ago
Plsss help i’ll give brainliest if you give a correct answer
Ugo [173]

Answer:

23

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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