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uranmaximum [27]
3 years ago
11

Martha spent $38.45 on a new shirt and now has $17.71 in her pocket.

Mathematics
1 answer:
Lelechka [254]3 years ago
8 0

Answer:

x + 17.71= 38.45

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=p%5E%7B3%7D%20at%20%5C%5C%5C%5C%20p%20%3D%202" id="TexFormula1" title="p^{3} at \\\\ p = 2" al
WITCHER [35]
<h3>Answer:  8</h3>

Reason:

Replace p with 2 and evaluate.

p^3 = 2^3 = 2*2*2 = 8

Think of a cube that is 2 units along each side. It's volume is 2*2*2 = 8 cubic units. Repeated multiplication can be shortened to using exponents.

Another example: 7^4 = 7*7*7*7

6 0
1 year ago
Can someone please answer. There is one problem. There's a picture. Thank you!
AnnZ [28]
Just multiply them so first multiply 2.7 times .9 and then times your answer by .6
4 0
3 years ago
Read 2 more answers
Does (lnk)/(k^3), where as k starts at one and continues on to infinity, converge? ...?
max2010maxim [7]
Yes. The numerator does not increase as fast as the denominator increases, causing the function's value to decrease with every subsequent increase in the value of k. This causes the function to converge at a point.
7 0
3 years ago
Mrs. Taylor bought a water tube to pull behind her boat. The tube cost $87.00 and 9% sales tax was added at the register. Mrs, T
wel
... cost $87.00 and 9% sales tax was added at the register. ms.taylor gave the cashier five $20 bills. how much change should she have received ...
6 0
3 years ago
I really am confused on how to write a proof.
kvasek [131]

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

\begin{gathered} AB=CD \\ BC=AD \end{gathered}

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

\begin{gathered} AE=CE \\ BE=DE \end{gathered}

Hence Proved.

8 0
1 year ago
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