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uranmaximum [27]
3 years ago
11

Martha spent $38.45 on a new shirt and now has $17.71 in her pocket.

Mathematics
1 answer:
Lelechka [254]3 years ago
8 0

Answer:

x + 17.71= 38.45

Step-by-step explanation:

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gavmur [86]

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3 years ago
Solve for x,y, and z.
Ann [662]

The given triangle is isosceles, so the two remaining angles in the triangle both have measure <em>xº</em>. The interior angles of any triangle sum to 180º, so that

58º + <em>xº</em> + <em>xº</em> = 180º

58 + 2<em>x</em> = 180

2<em>x</em> = 122

<em>x</em> = 61

Angles <em>y</em> and <em>z</em> are supplementary to angle <em>x</em>, so that

<em>xº</em> + <em>yº</em> = 180º

and

<em>xº</em> + <em>zº</em> = 180º

and consequently, <em>y</em> = <em>z</em>. In particular, we get

<em>y</em> = 180 - 61

<em>y</em> = 119

and so

<em>z</em> = 119

6 0
3 years ago
Billy is creating a circular garden divided into 8 equal sections. The diameter of the garden is 12 feet.
lubasha [3.4K]

Answer:

Step-by-step explanation:

area=πr^2

so we need to find the area then divide by 8

so

we know that diameter=2radius or diameter/2=radius so

12=diameter

12/2=radius=6

subsitute

area=π(6)^2

area=36π

divide 36π by 8

36π/8=18π/4=9π/2π=4.5π

area of one section is 4.5π square feet or if we aprox pito 3.14159 then we get

4.5(3.14159)=area=14.1372 square feet or 14.14 square feet

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3 years ago
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son4ous [18]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume
mixer [17]

Answer:

(a) 0.4096

(b) 0.64

(c) 0.7942

Step-by-step explanation:

The probability that the player wins is,

P(W)=0.80

Then the probability that the player losses is,

P(L)=1-P(W)=1-0.80=0.20

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = 1-P(L)-P(WL)

                                    =1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64

Thus, the probability that the player defeats at least two opponents in a game is 0.64.

(c)

Let <em>X</em> = number of times the player defeats all 4 opponents.

The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable X\sim Bin(n=3, p=0.4096)

The probability distribution of binomial is:

P(X=x)={n\choose x}p^{x} (1-p)^{n-x}

The probability that the player defeats all the 4 opponents at least once is,

P (<em>X</em> ≥ 1) = 1 - P (<em>X</em> < 1)

             = 1 - P (<em>X</em> = 0)

             =1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942

Thus, the probability that the player defeats all the 4 opponents at least once is 0.7942.

3 0
3 years ago
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