For (2), start with the base case. When n = 2, we have
(n + 1)! = (2 + 1)! = 3! = 6
2ⁿ = 2² = 4
6 > 4, so the case of n = 2 is true.
Now assume the inequality holds for n = k, so that
(k + 1)! > 2ᵏ
Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have
((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!
Then by our hypothesis,
(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹
and k•2ᵏ ≥ 2•2² = 8, so
k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹
which proves the claim.
Unfortunately, I can't help you with (3). Sorry!
Answer:
it's 112 both sides of the same and they're all so obtuse so therefore both of the other sides are the same
Step-by-step explanation:
Factor out the coefficient of the variable 2/3 j - 2/9
Answer
2/3j-2/9 = 2/3j-2/3*1/3 = 2/3(j-1/3)
this is the one that I did
Answer:
? = 36
Step-by-step explanation:
<em>Knowing that 3/5 and 24/40 is equal</em>
<em>Therefore we can either use:</em>
<em>3/5 = ?/60 or 24/40 = ?/60</em>
<em>I will use 3/5 = ?/60</em>
<em>Let ? = x</em>
<em>Hence we have</em>
<em>3/5 = x/60</em>
<em>Multiply both sides by 10</em>
<em>6 = x/6</em>
<em>Multiply both sides by 6</em>
<em>x = 36</em>
<em>Therefore, the question mark = 36</em>
<em />
<em>Let's check the answer by Simplifying the fraction:</em>
<em>3/5 = 36/60</em>
<em>3/5 is in already simplify</em>
<em>36/60 simplify = 3/5</em>
<em />
<em>3/5 = 3/5</em>
<em>Thus, the question mark = 36</em>
<em />
<em />
<u><em>[RevyBreeze]</em></u>
<em />
<em />