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3 years ago

Which explains whether Trina is correct

Mathematics

1 answer:

dangina [55]3 years ago

6 0

Answer:

because the two sides of the equation are equivalent

Step-by-step explanation:

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A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 12 inches. If the lizard is 8 inches from a

frez [133]

We will use the Pythagorean theorem:
8² + 12² = c²
64 + 144 = c²
c = √208 ≈ 14.42
14.42 - 12 = 2.42 in
The direct distance between the lizard and the cactus is 2.42 inches.

4 0

3 years ago

Twice the difference of a number and 2 is equal to three times the sum of the number and 3. Find the number. The number is nothi

trasher [3.6K]

The number is -13.

In order to find this, we first need to make each part of the statement into a mathematical statement.

Twice the difference of a number and 2.

2(x - 2)

Three times the sum of the number and 3

3(x + 3)

Now we can set them equal to each other and solve.

2(x - 2) = 3(x + 3) ----> Distribute

2x - 4 = 3x + 9 ------> Subtract 2x from both sides

-4 = x + 9 -----> Subtract 9 from both sides

-13 = x

3 0

3 years ago

Which expression has a value of 0?

oee [108]

My Question:

Is there any answer choices?

6 0

3 years ago

Each lap around the track is 400 meters. How many meters does someone run if they runs if Noah ran 14 laps, how many meters did

sashaice [31]

Question 1: You just do 400 x 14, and the answer is 5,600.
Question 2: You divide 7,600 by 400, and the answer is 19.

7 0

2 years ago

Read 2 more answers

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

5 0

3 years ago