A rectangular field is 115 yards long and 75 yards wide.

Can u pls help me with this question

Shalnov [3]

Answer:

A, C, D

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Mark wants to put a fence around his square yard.He knows that his yard is shaped like a square and the area of the yard is 110.

vichka [17]

Answer:

27.5 is the answer good luck

Step-by-step explanation:

good luck my G

3 0

3 years ago

What is the slope intercept form of an equation that goes through (-3,-5) and slope is 3/7

svet-max [94.6K]

Answer:

Step-by-step explanation:

Point slope form: y−7=34(x−3)

Slope intercept form: y=34x+194..or..y=34x+434

Explanation:

Since you have one point and the slope, you can use the point slope formula, then solve for y to get the slope intercept form, so that you can determine the y-intercept (b). Then you can graph the resulting equation.

Point slope formula

y−y1=m(x−x1), where x1,y1=(3,7), and m=34 is the slope.

Substitute the given values into the formula.

7 0

3 years ago

A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each

Nadya [2.5K]

Answer:

$312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

$\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}$ , where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

$\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}$

$\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3$

$\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3$

Therefore, the volume of earth removed to build the three tunnels is $312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$ .

4 0

3 years ago

The distance from the center of a carousel to the

anzhelika [568]

Answer:

$\fbox{\begin{minipage}{3.5em}338 (ft)\end{minipage}}$

Step-by-step explanation:

The problem could be simplified as following:

Given:

The radius of a circle O is 26 feet.

Solve for:

The length of arc on circle O that measures 13 radians

Solution:

Step 1: Let's find out the correct formula to apply:

The formula to calculate the length of an arc measuring x radians on a circle with radius r feet is:

L = r*x

Step 2: Let's put the data into formula to work out the length L of arc:

L = 26*13 = 338 (ft)

=> The distance that a horse does on the outer edge travel when the carousel rotates through 13 radians: L = 338 (ft)

Hope this helps!

:)

7 0

4 years ago