The answer is 11.25 mm.
A diameter of a circle is twice of its radius: d = 2r ⇒ r = d/2
small circle large circle
radius: r1 radius: r2 = ?
diameter: d1 = 15 mm
⇒ r1 = d1/2 = 15/2 mm
Since t<span>he ratio of the radii of two circles is 2:3, we have:
r1 : r2 = 2 : 3
which can also be expressed as:
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We know that r1 is 7.5, so let's implement it:
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Let's multiply both sides of the by 3r2:

⇒

⇒
Perpendicular lines will have negative reciprocal slopes
B. y = -4x+ 5 and y = 1/4x + 4
D. y = x + 4 and y = -x + 4
E. y = -3 and x = -3
Answer:
y + 30 = 4/5(x - 10)
Step-by-step explanation:
Given the slope, 4/5, and point (10, -30):
We can plug these values into the point-slope form:
y - y1 = m(x - x1)
Let (x1, y1) = (10, -30)
and m = 4/5
y - (-30) = 4/5(x - 10)
y + 30 = 4/5(x - 10)
Therefore, the point-slope form is y + 30 = 4/5(x - 10)
In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.
If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.
Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.
Make sure you draw a diagram of it!!