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3 years ago

-6+8x=-38 What is the answer and explain how you got it step by step

2 answers:

4 0

-6+8x=-38
move -6 to the right of the exppression
it become 8 * x -6=-38
8* x -6+38=0
8* x -6 +32=0
Added fractions or integers together
<span>It becomes 8*x +32=0
</span> 8*x+32=0
Solved <span>linear equation 8*x+32=0 </span>equivalent to 8*x+32 =0
it becomes 0=0
<span>
</span>
<span>This is an equation!</span><span> Solutions X=-4</span>

Anarel [89]3 years ago

3 0

-6 +8x = -38
8x = -32
x = -4
I did this by first adding 6 to both sides to get 8x by itself. I then divided by 8 to get x by itself. I remembered to use the - - + rule (Two negatives make a positive, a positive and a negative make a negative). Hope this helps!

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Find domain of y=rad20-6x

Evgesh-ka [11]

Domain, on an "even root" context, means, an even root cannot have a negative radicand, since say for example $\bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25$

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

$\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x$

now, if "x" is 10/3, let's see $\bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0$

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example $\bf x=\frac{11}{3}
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\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}$

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish

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Answer:

Step-by-step explanation:

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3 years ago

Solve the following problems mentally and match it to its corresponding solution.

HACTEHA [7]

Answer:

Step-by-step explanation:

Isolate the term of t from one side of the equation.

First, you have to divide by 4 from both sides.

4t/4=40/4

Solve.

Divide the numbers from left to right.

40/4=10

<u>First, change sides.</u>

t+10=14

<u>Then, subtract by 10 from both sides.</u>

t+10-10=14-10

<u>Solve.</u>

<u>Subtract the numbers from left to right.</u>

14-10=4

First, subtract by 70 from both sides.

70-t-70=30-70

Solve.

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<u>Rewrite the problem down.</u>

-t=-40

Divide by -1 from both sides.

-t/-1=-40/-1

<u>Solve.</u>

<u />

<u>Divide the numbers from left to right.</u>

-40/-1=40

<u>Therefore, the correct answer is t=10, t=4, and t=40.</u>

I hope this helps! Let me know if you have any questions.

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2 years ago

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