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2 years ago

Simplify b^10/b^2 OA. b^-8 OB. b^5 O c. b^-5 O D. b^8

Mathematics

1 answer:

Allushta [10]2 years ago

7 0

Step-by-step explanation:

The answer is D)

b^10/b^2

= b^10-b^2 = b^8

hope this helps.pls like and follow if you understand.

thanks:-):-)

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Which table contains only points that lie on the line of the equation y = 6x - 6?

Fittoniya [83]

Answer:

The answer is G

Step-by-step explanation:

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12 - 6 = 6

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2 years ago

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a ribbion is 3 2/3 yards long. Mae needs to cut the ribbion into pieces that are 2/3 yard long.how much ribbion will be left aft

Lemur [1.5K]

To answer this question you need to divide to get the number of pieces and then multiply whats leff by 3 2/3.

Divide 3 2/3 by 2/3. There are a few ways to do this but I am going to turn 3 2/3 into an improper fraction and then divide.

So $3\frac{2}{3} = \frac{11}{3}$
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We can see she can get 5.5 pieces at 2/3. So .5 is going to be left over so we ask our self, what is .5 of 3 2/3? We times .5 by 3 2/3 = 1.83 yards left. If you want it into a fraction, it would be $1\frac{83}{100}$ yards left

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2 years ago

Determine the value of x in the given diagram, when a║b.

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2 years ago

30 POINTS! Consider the system of linear equations and the matrix equations below.

fiasKO [112]

Answer:

Option C is correct.

Step-by-step explanation:

-x+3y=2

4x-2y=22

In matrix form is represented as:

$\left[\begin{array}{cc}-1&3\\4&-2\end{array}\right] \left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{c}2&22\end{array}\right]$

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|A| = (-1)(-2)-(3)(4)

|A| = 2-12

|A| = -10

Adj A = $\left[\begin{array}{cc}-2&-3\\-4&-1\end{array}\right]$

A^-1 = -1/10 $\left[\begin{array}{cc}-2&-3\\-4&-1\end{array}\right]$

A^-1 = 1/10 $\left[\begin{array}{cc}2&3\\4&1\end{array}\right]$

X= A^-1 B

X = 1/10 $\left[\begin{array}{cc}2&3\\4&1\end{array}\right]$ $\left[\begin{array}{c}2&22\end{array}\right]$

X=1/10 $X=1/10\left[\begin{array}{c}2*2+3*22\\4*2+1*22\end{array}\right]\\X=1/10\left[\begin{array}{c}4+66\\8+22\end{array}\right]\\X=1/10\left[\begin{array}{c}70\\30\end{array}\right]\\X=\left[\begin{array}{c}70/10\\30/10\end{array}\right]\\X=\left[\begin{array}{c}7\\3\end{array}\right]$

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Someone help me out here.

Vladimir [108]

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3 years ago