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3 years ago

Find the 10th term of an arithmetic sequence if the common difference is 32 and the first term is 2

Mathematics

1 answer:

zaharov [31]3 years ago

6 0

Answer:

290

Step-by-step explanation:

If the first term is 2 and the common difference is 32, then the formula for a(n) is:

a(n) = 2 + 32(n-1).

Thus, the 10th term is a(10) = 2 + 32(10-1) = 2 + 32(9) = 290

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The manager of a store that specializes in selling tea decides to experiment with a new blend. She will mix some Earl Grey tea t

marishachu [46]

Let us say that:

x = mass from Earl Grey Tea

y = mass from Orange Pekoe Tea

So that:

x + y = 600

and that:

6 x + 4 y = 4.5 * 600

6 (600 – y) + 4 y = 2700

3600 – 6y + 4y = 2700

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y = 450 pounds

x = 600 – 450 = 150 pounds

Answer:

Earl Grey Tea = 150 pounds

Orange Pekoe Tea = 450 pounds

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3 years ago

How do you graph -1/5x-1 and 4/5x-6

kakasveta [241]

Answer:

The points for the given to linear equations is (5 , - 2) and (5 , - 1)

The points is plotted on the graph shown .

Step-by-step explanation:

Given as :

The two linear equation are

y = $\dfrac{-1}{5}$ x - 1 ...........1

y = $\dfrac{4}{5}$ x - 6 ...........2

Now, Solving both the linear equations

Put the value of y from eq 2 into eq 1

I.e $\dfrac{4}{5}$ x - 6 = $\dfrac{-1}{5}$ x - 1

Or, $\dfrac{4}{5}$ x + $\dfrac{1}{5}$ x = 6 - 1

Or, $\dfrac{4 + 1}{5}$ x = 5

or, $\dfrac{5}{5}$ x = 5

∴ x = 5

Now, Put the value of x in eq 1

So, y = $\dfrac{-1}{5}$ x - 1

Or, y = $\dfrac{-1}{5}$ × 5 - 1

or, y = $\dfrac{-5}{5}$ - 1

Or, y = - 1 - 1

I.e y = -2

So, For x = 5 , y = - 2

Point is ( $x_1$ , $y_1$ ) = (5 , - 2)

Again , put the value of x in eq 2

So, y = $\dfrac{4}{5}$ x - 6

Or, y = $\dfrac{4}{5}$ × 5 - 6

Or, y = $\frac{4\times 5}{5}$ - 6

Or, y = 4 - 6

I.e y = - 2

So, For x = 5 , y = - 2

Point is ( $x_2$ , $y_2$ ) = (5 , - 2)

Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)

The points is plotted on the graph shown . Answer

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Answer:

Step-by-step explanation:

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Answer:

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