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3 years ago

3x=6y. i need help to turn that into y-intercept form and find tge y intercept. Help please

2 answers:

8 0

3x = 6y

to get this into slope-intercept form, you simply need to solve for y. remember that slope-intercept form is y = mx + b, where m is your slope and b is your y-intercept.

3x = 6y ... divide both sides by 6
1/2x = y
y = 1/2x is your equation in slope-intercept form. because no "b" value is present, your intercept will simply be 0.

Arisa [49]3 years ago

8 0

Tim Tele received a $380 discount loan to purchase a DVD player. The loan was offered at 18% for 60 days. Find the interest in dollars and the proceeds for the following problem.

The interest is $ <span>11.2211.0211.40</span>.

The proceeds are <span>368.78368.98368.60</span>.

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Fofino [41]

Answer:

Step-by-step explanation:

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3 years ago

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I need help and NOW PLEASE

mixas84 [53]

Answer:

a) 7/4 b) 15/2

Step-by-step explanation:

a) Scale Factor = Image / Object

Take the side of Triangle ABC that's BC Why? Because it corresponds with the Image Triangle ADE's DE

= 21/12 = 7/4

b) 7/4 = 10+ x / 10

Cross Multiply

= 4 ( 10 + x ) = 70

= 40 + 4x = 70

= 4x = 70-40

= 4x = 30

= 4x/4 = 30/4

x = 15/2

3 0

3 years ago

The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

olga nikolaevna [1]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\$ $\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
% (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
solve\ for\ x_2\ and\ y_2$

3 0

3 years ago

there are 3/4 as many boys as girls in a class of fifth-graders if there are 35 students in the class how many a

Arlecino [84]

Alright so turn 3/4 into a decimal.
3/4 =.75

We need to set up an equation. To do that are need to give boys and girls their own variables.

Girls= X

And since there is 3/4 as many boys
Boys=. 75X

Now we know the sum of boys and girls equals 35
X+.75X=35

X+.75X=1.75X
Now we have 1.75X=35

Divide by 1.75 and get
20=X

Now plug 20 into the equations got from before.
Boys =. 75*X = 20 *. 75 = 15
Girls = X =20

Your Answer:
15 boys
20 girls

You can check
20+15=35
15/20=3/4

8 0

3 years ago

Read 2 more answers

What is another point on the line?

Kamila [148]

Answer:

B. (0,9)

Step-by-step explanation:

Start the point on (4,3), and becasue the slope is -3/2 you do rise over run. so you could go up 3 and left 2 or down 3 and right 2. i went up 3 and left to twice from point (4,3) and arrived at point (0,9). so the answer is B. (0,9)

7 0

3 years ago