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kiruha [24]
3 years ago
11

What is the sum of 12-5¡ and -3+4¡

Mathematics
2 answers:
Tpy6a [65]3 years ago
6 0

Answer:

8

Step-by-step explanation:

hope t helped

Goshia [24]3 years ago
5 0

Answer:

8

Step-by-step explanation:

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lakkis [162]

2.05 I think if the question was just 4 1/10 ÷2

5 0
2 years ago
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Which term of the AP. 8 , -4 , -16 , -28 ,......... is -880 ?​
denis-greek [22]

Answer:

75th term

Step-by-step explanation:

hope it is well understood

6 0
3 years ago
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A certain bay with very high tides displays the following behavior. In one 12-h period the water starts at mean sea level, rises
Firdavs [7]

Answer:

the required equation is; y = 21 sin(πt/6)

Step-by-step explanation:

Given the data in the question;

Water rises above sea level = 21 ft

Water drops below sea level = 21 ft

so

maximum = 21 ft and also

minimum = 21 ft

Amplitude = ( maximum + minimum ) / 2

Amplitude = ( 21 + 21 ) / 2

Amplitude = ( 21 + 21 ) / 2 = 42/2 = 21 ft

Period = 12 hours

and we know that; period = 2π/b

so

12 = 2π/b

12b = 2π

b = 2π / 12

b = π/6

Standard equation for simple harmonic is; y = asin(bt)

we substitute

y = 21 sin(πt/6)

Hence the required equation is; y = 21 sin(πt/6)

7 0
3 years ago
Solve 2x2 − 8x = −7.
leva [86]
\sf 2x^2 - 8x = - 7  \\  \\ Subtract \ -7 \ from \ both \ sides \ of \ the \ equation. \\  \\ 2x^2 - 8x - (-7 ) = - 7 - (-7)  \\  \\ 2x^2 - 8x + 7 = 0  \\  \\ Use \ quadratic \ formula \ a = 2, b = -8, c = 7 \\  \\ x =  \dfrac{- b \pm \sqrt{b^2- 4ac} }{2a}  \\  \\  \\ x =  \dfrac{-(-8) \pm \sqrt{(-8)^2 - 4 (2) (7) } }{2(2)}  \\  \\ x =  \dfrac{8 \pm  \sqrt{8} }{4}  \\  \\ x = 2 +  \frac{1}{2}\sqrt{2} \ or \ x = 2 +  \frac{-1}{2}  \sqrt{2}

Ur answer is the fourth one 



7 0
3 years ago
Read 2 more answers
6. Which value of x makes the equation below true?<br> 5x - 3 = 11 A. 1.6 B. 2.8 C. 40<br> D. 70
Harlamova29_29 [7]

Answer:

It's B

Step-by-step explanation:

2 times 5 = 10

0.8 times 5=4

10 + 4 =14

14-3=11

8 0
2 years ago
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