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3 years ago

Which expression is equivalent to 1/4 n - 16

Mathematics

1 answer:

Anit [1.1K]3 years ago

7 0

9514 1404 393

Answer:

b 1/4 (n-64)

Step-by-step explanation:

Multiplying the expression by 1 does not change its value:

= (1/4)(4) × (1/4n -16)

= (1/4) × (4(1/4n -16)) . . . . . associative property

= (1/4) × ((4/4)n -4·16) . . . . distributive property

= (1/4)(n -64) . . . . matches choice B

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3 years ago

A solid object is dropped into a pond with a temperature of 20 degrees Celsius. The function f(t)=Ce(−kt)+20 represents the situ

LenaWriter [7]

Answer:

The initial temperature of the object was 37.6 degrees Celsius

The initial temperature of the object was 37.6 (without units)

Step-by-step explanation:

we have

$f(t)=Ce^{(-kt)} +20$

where

f(t) represent the temperature of the object in degree Celsius

t is the time in minutes

Find the value of the constant C

we have the ordered pair (4,35)

substitute in the equation and solve for C

$35=Ce^{(-0.0399*4)} +20$

$Ce^{(-0.0399*4)}=15$

$C=15/e^{(-0.0399*4)}$

$C=17.6$

Find the initial value of the object

we know that

The initial temperature is the value of f(t) when the value of t is equal to zero

For t=0

$f(0)=(17.6)e^{(-k*0)} +20$

$f(0)=17.6 +20$

$f(0)=37.6\ degrees\ Celsius$

therefore

The initial temperature of the object was 37.6 degrees Celsius

The initial temperature of the object was 37.6 (without units)

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3 years ago

Is 1/9 closer to 0 or closer 1/2

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1/9 is closer to 0

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The product of two integers is eighty,their quotient is five.Write both integers in numerical order and separated by a comma,no

Goryan [66]

SOLUTION

Let the two integers be x and y.

Now, the product of x and y, is 80, that is

$\begin{gathered} x\times y=80 \\ xy=80\ldots\ldots\text{.equation 1} \end{gathered}$

The quotient of x and y is 5, that is

$\begin{gathered} x\div y=5 \\ \frac{x}{y}=5\ldots\ldots\ldots\ldots\text{.}\mathrm{}\text{equation 2} \end{gathered}$

From equation 2, make x, the subject, we have

$\begin{gathered} \frac{x}{y}=5 \\ \text{cross multiplying } \\ 5\times y=x \\ x=5y \end{gathered}$

Now substitute the x for 5y into equation 1, we have

$\begin{gathered} xy=80 \\ 5y\times y=80 \\ 5y^2=80 \\ \text{dividing by 5} \\ y^2=\frac{80}{5} \\ y^2=16 \\ \text{take square root of both sides } \\ \sqrt[]{y^2}=\sqrt[]{16} \\ \text{square cancels root} \\ y=4 \end{gathered}$

Now substitute y for 4 into any of the equations.

Let us use equation 1 again, we have

$\begin{gathered} xy=80 \\ x\times4=80 \\ 4x=80 \\ x=\frac{80}{4} \\ x=20 \end{gathered}$

Hence the answer is 4, 20

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1 year ago