<u><em>Question</em></u>
<em>If the CP of 15 articles equals to the SP of 12 articles, find the gain percent.</em>
<em></em>
Answer:
gain percent = 25%
Step-by-step explanation:
To solve the question given, we will follow the steps below:
gain% =
× 100%
But from the question;
"CP of 15 articles equals to the SP of 12 articles", this implies that
15 c.p = 12 s.p
s.p = 15c.p / 12
s.p =
= 
s.p = 
substitute s.p =
into the formula
gain% =
× 100%
=
× 100%
=
× 100%
=
÷ c.p × 100%
=
×
× 100%
=
× 100%
= 25 %
Answer:
Here is the ans hope it helps:)
Answer:
59062.50
Step-by-step explanation:
Is means equals
9450 = 16% of a number
9450 = .16 N
divide by .16
9450/.16 = .16N/.16
59062.50 = N
The number is 59062.50
We want 100% of the number which is all of it
59062.50
Answer:
Volume is 20.93333333 units^3
Step-by-step explanation:
I used 3.14 for pi
Look at the attachment
Area = 2831.25 square yards
Perimeter =215.6 yards
EXPLANATION
The area and perimeter of a rectangular field are found using the formula for finding the area and perimeter of a rectangle respectively.
That means, area of the rectangular field is given by the formula,

We just have to substitute

and

into the given formula and evaluate.
This implies that;

This gives the area of the rectangular-shaped field to be;

square yards.
Now for the perimeter, we use the formula

Or

Substituting the values for the length and width gives,



Hence the perimeter of the rectangular shaped field is 215.6 yards.