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lesantik [10]
3 years ago
5

Only need #2 plz i know the answer is B i just don’t know why

Mathematics
2 answers:
Luda [366]3 years ago
8 0

Check the picture below.

so, if we grab that sector made by UGD, like you see in the picture, we revolve it to the left-side and behind, we'll end up really with a half of a sphere, whose radius is 8.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=8 \end{cases}\implies V=\cfrac{4\pi 8^3}{3}\implies V=\cfrac{2048\pi }{3} \\\\\\ \stackrel{using~\pi =3.14}{V=2143.57}\implies \stackrel{\textit{half of that for a semi-sphere}}{V\approx 1071.78\overline{6}}\implies \stackrel{\textit{rounded up}}{V=1071.79}

disa [49]3 years ago
6 0

The rotation about UG would generate a hemisphere of radius 8. The volume of a sphere with radius r is \dfrac43\pi r^3, so the volume of the hemisphere would be \dfrac12\cdot\dfrac43\pi 8^3\approx\dfrac{1024\cdot3.14}3\approx1071.79.

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Suppose that the thickness of one typical page of a book printed by a certain publisher is a random variable with mean 0.1 mm an
marusya05 [52]

Answer:

The probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm is 0.97.

Step-by-step explanation:

The complete question is:

Suppose that the thickness of one typical page of a book printed by a certain publisher is a random variable with mean 0.1 mm and a standard deviation of 0.002 mm Anew book will be printed on 500 sheets of this paper. Approximate the probability that the thicknesses at the entire book (excluding the cover pages) will be between 49.9 mm and 50.1 mm. Note: total thickness of the book is the sum of the individual thicknesses of the pages Do not round your numbers until rounding up to two. Round your final answer to the nearest hundredth, or two digits after decimal point.

Solution:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e S, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{S}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

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The information provided is:

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As <em>n</em> = 500 > 30, the central limit theorem can be used to approximate the total thickness of the book.

So, the total thickness of the book (S) will follow N (50, 0.045²).

Compute the probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm as follows:

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Thus, the probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm is 0.97.

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Step-by-step explanation:

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