Question

Hich of the following is an even function? f(x) = (x – 1)2 f(x) = 8x f(x) = x2 – x f(x) = 7

Answer 1

Answer:

f(x) = 7 is an even function.

Step-by-step explanation:

Any function is even when $f(x) = f(-x)$ and gives a graph that is symmetric with respect to the y-axis.

We are given these options and we have to check whether which of them is an even function:

$f(x)= (x-1)^2$ $= x^2-2x+1$

and $f(-x) = (-x - 1)^2 = x^2 + 2x + 1$ - This function is not even

$f(x) = 8x$

and $f(-x) = -8x$ - This function is not even

$f(x)=x^2-x$

and $f(-x) = (-x)^2 + x = x² + x$ - This function is not even

$f(x) = 7$

and $f(-x) = 7$ - EVEN FUNCTION

We get the same value for $f(x)$ and $f(-x)$, therefore f(x) = 7 is an even function.

Answer 2

All of these are functions except for f(x)=7, because there must be an "x" in there somewhere. There is no real way to graph f(x)=7, because it is not a function.  :)