|DF| = |DE| + |EF| |DF| = 9x -36 |DE| = 47 |EF| = 3x+10 Substitute: 9x - 39 = 47 + 3x + 10 9x - 39 = 3x + 57 |+39 9x = 3x + 96 |-3x 6x = 96 |:6 x = 16 Put the value of x to the equation |EF| = 3x + 10 |EF| = (3)(16) + 10 = 48 + 10 = 58 Answer: |EF| = 58
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Answer:
6
Step-by-step explanation:
18.3/3.05=6
18.3 / 6=3.05
Answer:
Exact form : 5723^9
Decimal form : 6.58587848 • 10^33
Step-by-step explanation: Evaluate.
Hope this helps you out! ☺
Answer:
The area between z = 1.74 and z = 1.25 is of 0.065.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The area between two values of Z is given by the subtraction of the pvalue of the larger value by the smaller.
The area between z = 1.74 and z = 1.25.
This is the pvalue of z = 1.74 subtracted by the pvalue of z = 1.25.
z = 1.74 has a pvalue of 0.959
z = 1.25 has a pvalue of 0.894
0.959 - 0.894 = 0.065
The area between z = 1.74 and z = 1.25 is of 0.065.
Answer:
4:12 6:18 :) I hope this is ok (I haven't done ratios in a while lol)