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lina2011 [118]
3 years ago
10

What equation could be written for this table?

Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

y = 3 + 1/2 * x

Step-by-step explanation:

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Solve the equation for W and L
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Answer:

Step-by-step explanation:

Cross multiply and get:

\sqrt{7}L = 5w

L = 5w/\sqrt{7}

W = \sqrt{7}L/5

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Determine the vertical asymptote for the rational function f(x) = x - 4 over 2x + 3.
mr_godi [17]

Vertical asymptotes happen at x=a if the function is undefined at x=a.

This is a rational functions, and rational functions are not defined when the denominator is zero, since you can't divide by zero.

In this case, the denominator is zero if

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3 years ago
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AfilCa [17]

The given equation is

\begin{gathered} \log (x^4+3x^3)-\log (x+3)+\log 2-\log 6=2\log x \\ \log (\frac{x^4+3x^{3^{}}}{x+3})+\log \frac{2}{6}=\log x^2 \\ \log \frac{x^3(x+3)}{x+3}+\log \frac{1}{3}=\log x^2 \\ \log x^3+\log \frac{1}{3}=\log x^2 \\ \log \frac{x^3}{3}=\log x^2 \\ \frac{x^3}{3}=x^2 \\ x^3-3x^2=0 \\ x^2(x-3)=0 \end{gathered}

hence

x=0\text{ or x=3}

But x cannot be zero so x=3

So the value of x is 3

h

7 0
1 year ago
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