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2 years ago

What equation could be written for this table?

Mathematics

1 answer:

kkurt [141]2 years ago

7 0

Answer:

y = 3 + 1/2 * x

Step-by-step explanation:

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A dance school has 54 students who learn salsa

Archy [21]

They should be 54 students who know how to salsa

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

2 years ago

Holly has $125 she spends $35 on gas for her car which model represents how much money holly has left idk if the answer is right

inn [45]

Answer:

The second one would be the answer.

Step-by-step explanation:

If you look at the model, it shows it on 125 going down to 90.

If she has $125 and she spends $35 on gas, you would subtract that from how much money she has.

125 - 35 = 90.

Feel free to let me know if you need more help. :)

5 0

3 years ago

What is the correct answer

anzhelika [568]

A and D
should be the answers.

5 0

3 years ago

?????????????? help out

dimaraw [331]

Answer:

20 degrees C

Step-by-step explanation:

You would substitute the F with 68 since it is 68 degrees F. Then you would solve the equation. (Subtract 32 from 68=36; multiply 36 by 5/9=20)

5 0

3 years ago