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lutik1710 [3]
3 years ago
12

Lugar geométrico infinito formado por un conjunto de puntos que conservan la misma dirección

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0

Answer:

l lugar geométrico de los puntos que equidistan a otros dos puntos fijos {\displaystyle A}A y {\displaystyle B}B es una recta o eje de simetría de dichos dos puntos. Si los dos puntos son los dos extremos de un segmento {\displaystyle {\overline {AB}}}\overline {AB}, dicha recta, o lugar geométrico, es llamada mediatriz y es la recta que interseca perpendicularmente a {\displaystyle {\overline {AB}}}\overline {AB} en su punto medio.

La bisectriz cumple la propiedad de que todos sus puntos equidistan a los lados de dicho ángulo, convirtiéndose la bisectriz en un caso particular del lugar geométrico que sigue a continuación.

El caso de equidistancia a dos rectas paralelas, obtenemos que la paralela media es el lugar geométrico de los puntos que las equidistan. Se observa que, bajo el punto de vista de que las rectas paralelas se cortan en el infinito -se elimina, pues, la noción de paralelismo-, pasa a ser un sinónimo de la bisectriz, donde el ángulo ha tomado valor nulo.

Secciones cónicas

Las secciones cónicas pueden ser descritas mediante sus lugares de geométria:

La circunferencia es el lugar geométrico de los puntos cuya distancia a un punto determinado, el centro, es un valor dado (el radio).

La elipse es el lugar geométrico de los puntos tales que la suma de su distancia a dos puntos fijos, los focos, es una constante equivalente a la longitud del eje mayor de la elipse.

La parábola es el lugar geométrico de los puntos cuya distancia a un foco equivale a su distancia a una recta llamada directriz.

La hipérbola es el lugar geométrico de los puntos tales que el valor absoluto de la diferencia entre sus distancias a dos puntos fijos, los focos, es igual a una constante (positiva), que equivale a la distancia entre los vértices.

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There is a 2% probability that the student is proficient in neither reading nor mathematics.

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We solve this problem building the Venn's diagram of these probabilities.

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B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

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(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

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Calculating the discriminant b^2 - 4ac, we get (-1)^2 - 4(3)(-9), or 1 + 108, or 109.  Because the discriminant is positive, we have two real, unequal roots.

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